How do you find a vector of length 10 in the direction of v equals=left angle 3 comma negative 2 right angle 3,−2?
1 answer:
You might be interested in
A) Let x stand for time, y stand for velocity.
We are given the points (2,50), (6, 54). We can make a line using the slope intercept form
y = mx + b.
slope is (54 - 50)/(6-2) = 4/4 = 1
y = 1x + b
plug in point (2,50) to find b
50 = 1(2) + b
50-2 = b
48 = b
the equation is y = 1x + 48
Make standard form.
<span>x - y = -48
</span><span>b) make a table and plot points for the first 7 hours
Table Is attached.
Good Luck!
If you like the answer please give me brainliest answer!
</span>
We are given the points (2,50), (6, 54). We can make a line using the slope intercept form
y = mx + b.
slope is (54 - 50)/(6-2) = 4/4 = 1
y = 1x + b
plug in point (2,50) to find b
50 = 1(2) + b
50-2 = b
48 = b
the equation is y = 1x + 48
Make standard form.
<span>x - y = -48
</span><span>b) make a table and plot points for the first 7 hours
Table Is attached.
Good Luck!
If you like the answer please give me brainliest answer!
</span>