How do you find a vector of length 10 in the direction of v equals=left angle 3 comma negative 2 right angle 3,−2?
1 answer:
Your vector will be 10 times the unit vector in that direction. The unit vector is found by dividing the given vector by its length.
|| <3, -2> || = √(3² +(-2)²) = √13
Your vector of length 10 is then
... V = (10/√13)<3, -2> = <(30/13)√13, (-20/13)√13> ≈ <8.32, -5.55>
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Answer:
3
Step-by-step explanation:
17+x+12-0=32
29+x-0=32
29+x+32
x=32-29
x=3
Assuming cos means cos(x);
Combine all like terms: cos(x)(√2 - 12)= -1
Isolate x: cos(x)= -1/(√2 - 12)
cos(x)=0.0944
x=cos⁻¹(0.0944)
x= 84.57 degrees or (360-x=275.42 degrees)
Hope I helped :)
All real numbers are solutions, let me know if you need an explanation luv
Goran completes 6. karen completes 10. it takes 60 minutes
8(p-2) = 32
8p - 16 = 32
+16 on each side
8p= 48
Divide by 8 on each side
P= 6
