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3 years ago

BRAINLIEST!!!

Mathematics

2 answers:

Papessa [141]3 years ago

4 0

For the equation, the rate of change would be four.
Now looking at the graph, look at each point of the line that hits perfectly on a grid. Count up four, over two. The rate of change for the graph would be 4/2, or 2. Hope this helps!

ankoles [38]3 years ago

4 0

Hi there!

Graph:
The rate of change is 2.

If we take the points (3,2) and (1, -2) and use slope triangles to find the slope, 4 ÷ 2 = 2, so the slope is 2.

Function:
The rate of change is 4.
The rage of change in a function in slope intercept form is always the number before x.

Hope this helps!

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If -2x+xy=30 and y=8,then what is the value of x?

Dafna1 [17]

-2x + xy = 30.....when y = 8

-2x + 8x = 30
6x = 30
x = 30/6
x = 5 <==

3 0

3 years ago

Read 2 more answers

If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple ar

Oksana_A [137]

Answer:

$n + 4 {n \choose 2} + 6 {n \choose 3} + 4 {n \choose 4} + {n \choose 5}$

Step-by-step explanation:

Lets divide it in cases, then sum everything

Case (1): All 5 numbers are different

In this case, the problem is reduced to count the number of subsets of cardinality 5 from a set of cardinality n. The order doesnt matter because once we have two different sets, we can order them descendently, and we obtain two different 5-tuples in decreasing order.

The total cardinality of this case therefore is the Combinatorial number of n with 5, in other words, the total amount of possibilities to pick 5 elements from a set of n.

${n \choose 5 } = \frac{n!}{5!(n-5)!}$

Case (2): 4 numbers are different

We start this case similarly to the previous one, we count how many subsets of 4 elements we can form from a set of n elements. The answer is the combinatorial number of n with 4 ${n \choose 4} .$

We still have to localize the other element, that forcibly, is one of the four chosen. Therefore, the total amount of possibilities for this case is multiplied by those 4 options.

The total cardinality of this case is $4 * {n \choose 4} .$

Case (3): 3 numbers are different

As we did before, we pick 3 elements from a set of n. The amount of possibilities is ${n \choose 3} .$

Then, we need to define the other 2 numbers. They can be the same number, in which case we have 3 possibilities, or they can be 2 different ones, in which case we have ${3 \choose 2 } = 3$ possibilities. Therefore, we have a total of 6 possibilities to define the other 2 numbers. That multiplies by 6 the total of cases for this part, giving a total of $6 * {n \choose 3}$

Case (4): 2 numbers are different

We pick 2 numbers from a set of n, with a total of ${n \choose 2}$ possibilities. We have 4 options to define the other 3 numbers, they can all three of them be equal to the biggest number, there can be 2 equal to the biggest number and 1 to the smallest one, there can be 1 equal to the biggest number and 2 to the smallest one, and they can all three of them be equal to the smallest number.

The total amount of possibilities for this case is

$4 * {n \choose 2}$

Case (5): All numbers are the same

This is easy, he have as many possibilities as numbers the set has. In other words, n

Conclussion

By summing over all 5 cases, the total amount of possibilities to form 5-tuples of integers from 1 through n is

$n + 4 {n \choose 2} + 6 {n \choose 3} + 4 {n \choose 4} + {n \choose 5}$

I hope that works for you!

4 0

3 years ago

Find a formula for the sum of the first n even integers : 2 + 4 + 6 + ... + 2n.

Sedbober [7]

Let S be the sum,

S = 2 + 4 + 6 + ... + 2 (n - 2) + 2 (n - 1) + 2n

Reverse the order of terms:

S = 2n + 2 (n - 1) + 2 (n - 2) + ... + 6 + 4 + 2

Add up terms in the same positions, so that twice the sum is

2S = (2n + 2) + (2n + 2) + (2n + 2) + ... + (2n + 2)

2S = n (2n + 2)

Divide both sides by 2 to solve for S :

S = n (n + 1)

7 0

2 years ago

A car salesman sells cars with prices ranging from $5,000 to $45,000. The histogram shows the distribution of the numbers of car

iogann1982 [59]

It's either 20 or 25 thousand.

8 0

3 years ago

The base of the right triangle drawn in the regular octagon measures 0.7 cm.

Otrada [13]

Answer:

11.2

Step-by-step explanation:

a right triangle in an octagon is 1/2 a side length so to find the side length you must add .7 + .7. Next to find the perimeter of the octagon you must multiply the number of sides 8 by .14 which equals 11.2

5 0

3 years ago

Read 2 more answers