Answer:
Explanation:
Using freezing point depression formula,
ΔTemp.f = Kf * b * i
Where,
ΔTemp.f = temp.f(pure solvent) - temp.f(solution)
b = molality
i = van't Hoff factor
Kf = cryoscopic constant
= 1.86°C/m for water
= (0 - (-5.58))/1.86
= 3.00 mol/kg
Assume 1 kg of water(solvent)
= (3.00 x 1)
= 3.00 mol.
Answer:
Conversely, as one progresses down a group on the periodic table, the ionization energy will likely decrease since the valence electrons are farther away from the nucleus and experience greater shielding. They experience a weaker attraction to the positive charge of the nucleus.
Answer:
P₂ = 1530.1 KPa
Explanation:
According to Bolye's Law,
The volume of given mass of a gas is inversely proportional to the pressure applied on it at a constant temperature.
V∝1/P
V = kP
V = K/P
PV = k
According to this equation,
P₁V₁ = P₂V₂
Given data:
Initial volume = 456 dm³
Initial pressure = 101 KPa
Final volume = 30.1 dm³
Final pressure = ?
Solution:
Formula:
P₁V₁ = P₂V₂
P₂ = P₁V₁ / V₂
P₂ = 101 KPa × 456 dm³ / 30.1 dm³
P₂ = 46056 / 30.1 dm³
P₂ = 1530.1 KPa
The region of the periodic table that do the elements not normally react chemically with other elements is noble gases(answer D)
Explanation
- Nobles gases are element in group 18 in periodic table.
- They have 8 electrons in their outermost energy level( <em>their valence electrons are fully filled)</em>
- This make noble gases inert ( an reactive ) since they cannot gain or loss electron .
Answer:
All you have to do here is use the ideal gas law equation, which looks like this
P
V
=
n
R
T
−−−−−−−−−−
Here
P
is the pressure of the gas
V
is the volume it occupies
n
is the number of moles of gas present in the sample
R
is the universal gas constant, equal to
0.0821
atm L
mol K
T
is the absolute temperature of the gas
Rearrange the equation to solve for
T
P
V
=
n
R
T
⇒
T
=
P
V
n
R
Before plugging in your values, make sure that the units given to you match those used in the expression of the universal gas constant.
In this case, the volume is given in liters and the pressure in atmospheres, so you're good to go.
Plug in your values to find
T
=
3.10
atm
⋅
64.51
L
9.69
moles
⋅
0.0821
atm
⋅
L
mol
⋅
K
T
=
251 K
−−−−−−−−−
The answer is rounded to three sig figs
Explanation:
hope it helps
