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Doss [256]
3 years ago
8

A bag contains blue and yellow marbles. Two marbles are drawn without replacement. The probability of selecting a blue marble an

d then a yellow marble is 0.37, and the probability of selecting a blue marble on the first draw is 0.55.
What is the probability of selecting a yellow marble on the second draw, if the first marble drawn was blue?
A) 18%
B) 20%
C) 46%
D) 67%
Mathematics
1 answer:
igomit [66]3 years ago
4 0
Let b = blue marbles
y = yellow marbles
 Sum = b+y
 The <span>chance of a blue marble being drawn first is:
b / (b+y) = 0.55 
</span>The <span>chance of a blue marble being drawn first then a yellow next is:
</span>b / (b+y) * <span>y / (b+y-1) = 0.37</span>
This can be solve easily by using a theorem of Bayes 
0.37/0.55 = .67 or 67%
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The length of the rectangular tennis court at wimbledon is 6 feet longer than twice the width. if the court's perimeter is 240 f
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Length (L): 2w + 6

width (w): w

Perimeter (P) = 2L + 2w

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Of 100 students,65 are members of a mathematics club and 40 are members of a physics club. if 10 are members of neither club the
alexandr1967 [171]

a. 15 students are members of both clubs

b. 50 students only are members of the mathematics club

c. 25 students only are members of the physics club

Step-by-step explanation:

The given is:

  • There are 100 students
  • 65 are members of a mathematics club
  • 40 are members of a physics club
  • 10 are members of neither club

We need to find how many students are members of

a. both clubs?

b. only mathematics club

c. only physics club

∵ The total number of students = 100

∵ 10 are members of neither club

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  club or the physics club

∵ 100 - 10 = 90

∴ There are 90 members of the mathematics club or physics club

∴ n(mathematics or physics) = 90

∵ 65 students are members of a mathematics club

∵ n(mathematics) = 65

∵ 40 students are members of a physics club

∴ n(physics) = 40

∵ n(mathematics or physics) = n(mathematics) + n(physics) - n(both)

∴ 90 = 65 + 40 - n(both)

∴ 90 = 105 - n(both)

- Add n(both) to each side

∴ n(both) + 90 = 105

- Subtract 90 from each side

∴ n(both) = 15

∴ 15 students are members of both clubs

a. 15 students are members of both clubs

∵ 65 students are members of the mathematics club

∵ 15 of them are members of the physics club

∴ n(mathematics only) = 65 - 15 = 50

∴ 50 students only are members of the mathematics club

b. 50 students only are members of the mathematics club

∵ 40 students are members of the physics club

∵ 15 of them are members of the mathematics club

∴ n(physics only) = 40 - 15 = 25

∴ 25 students only are members of the physics club

c. 25 students only are members of the physics club

Learn more:

You can learn more about word problems in brainly.com/question/8907574

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Step-by-step explanation:

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