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Doss [256]
3 years ago
8

A bag contains blue and yellow marbles. Two marbles are drawn without replacement. The probability of selecting a blue marble an

d then a yellow marble is 0.37, and the probability of selecting a blue marble on the first draw is 0.55.
What is the probability of selecting a yellow marble on the second draw, if the first marble drawn was blue?
A) 18%
B) 20%
C) 46%
D) 67%
Mathematics
1 answer:
igomit [66]3 years ago
4 0
Let b = blue marbles
y = yellow marbles
 Sum = b+y
 The <span>chance of a blue marble being drawn first is:
b / (b+y) = 0.55 
</span>The <span>chance of a blue marble being drawn first then a yellow next is:
</span>b / (b+y) * <span>y / (b+y-1) = 0.37</span>
This can be solve easily by using a theorem of Bayes 
0.37/0.55 = .67 or 67%
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The length of a rectangle is 5 inches less than twice its width. The perimeter of the rectangle is 26 inches. What is the width
Yakvenalex [24]

Answer:

w= 6

Step-by-step explanation:

I just started by making an educated guess using the values already given. Then I inserted that into the problem to see if it worked.

L= 2w - 5

I used 6 as a random, educated guess for the value of w.

L = 2(6) - 5

L = 12-5

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Then, multiply L by 2 to account for both side lengths of the rectangle.

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Subtract that value from the total perimeter to find what the width must equal.

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Divide that answer by 2 since there are two sides for width.

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2 years ago
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spayn [35]

Answer:

The second option: 3 (6 - 5n)/20n

Step-by-step explanation:

Make sure all fractions have a common denominator:

Step 1. Find a common multiple between all three denominators

5, 4, and 10 all have a common multiple of 20. Proof: 5 × 4 = 20, 4 × 5 = 20, and 10 × 2 = 20

Step 2. Multiply the denominators to get to 20. Whatever you do to the bottom (denominator) must be done to the top (numerator).

1/5n × 4/4 = 4/20n

3/4 × 5n/5n = 15n/20n

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Your fractions now all have a common denominator of 20n.

Rewrite the equation using the new fractions:

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Only focus on adding/subtracting the numerators; the denominators will stay the same: 20n.

(4 - 15n + 14)/20n

Combine like terms:

(18 - 15n)/20n

Factor out any numbers possible:

3(6 - 5n)/20n

Note* 3 go into both 18 and 15, which allows us to factor 3 out. 18 ÷ 3 = 6 and 15 ÷ 3 = 5, giving us our new numbers inside the parentheses.

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