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stiks02 [169]
3 years ago
7

What is the final temperature of a 27.2-gram wooden block that starts at 23.4 degrees celsius and loses 759 joules of energy? Th

e specific heat capacity of wood is 1.716 joules/gram degree Celsius.
Chemistry
1 answer:
Marrrta [24]3 years ago
3 0

Answer:

The correct answer is 7.1 degree C.

Explanation:

Based on the given information, the initial temperature or To of the block is 23.4 degree C.  

The energy lost or Q from the given wooden block is -759 J.  

The specific heat capacity or c of the wood given is 1.716 J/g°C

The mass of the wooden block given is 27.2 grams.  

There is a need to find the final temperature of the wooden block, for this the formula to be used is,  

Q = m × c × (T-To)

Now by putting the given values in the formula we get,  

-759 = 27.2 × 1.716 (T - 23.4)

T = 7.1 degree C.  

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Answer:

\boxed {\boxed {\sf 0.3 \ mol \ NaNO_3}}

Explanation:

Molarity is a measure of concentration in moles per liter.

molarity= \frac{moles \ of \ solute}{liters \ of \ solution}

The molarity of the solution is 1.2 M NaNO₃ or 1.2 moles NaNO₃ per liter. There are 0.25 liters of the solution. The moles of solute are unknown, so we can use x.

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1.2 \ mol \ NaNO_3/L= \frac{x}{0.25 \ L}

We are solving for x, so we must isolate the variable, x. It is being divided by 0.25 liters. The inverse of division is multiplication, so we multiply both sides by 0.25 L.

0.25 \ L *1.2 \ mol \ NaNO_3/L=\frac{x}{0.25 \ L} *0.25 \ L

0.25 \ L *1.2 \ mol \ NaNO_3/L=x

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There are 0.3 moles of sodium nitrate.

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2 years ago
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