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stiks02 [169]
3 years ago
7

What is the final temperature of a 27.2-gram wooden block that starts at 23.4 degrees celsius and loses 759 joules of energy? Th

e specific heat capacity of wood is 1.716 joules/gram degree Celsius.
Chemistry
1 answer:
Marrrta [24]3 years ago
3 0

Answer:

The correct answer is 7.1 degree C.

Explanation:

Based on the given information, the initial temperature or To of the block is 23.4 degree C.  

The energy lost or Q from the given wooden block is -759 J.  

The specific heat capacity or c of the wood given is 1.716 J/g°C

The mass of the wooden block given is 27.2 grams.  

There is a need to find the final temperature of the wooden block, for this the formula to be used is,  

Q = m × c × (T-To)

Now by putting the given values in the formula we get,  

-759 = 27.2 × 1.716 (T - 23.4)

T = 7.1 degree C.  

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A rotameter calibration curve (flow rate versus float position) obtained using a liquid is mistakenly used to measure a gas flow
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A sample of an ideal gas at 1.00 atm and a volume of 1.84 L was placed in a weighted balloon and dropped into the ocean. As the
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Answer:

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Explanation:

Given data

  • Initial pressure (P₁): 1.00 atm
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  • Final pressure (P₂): 30.0 atm
  • Final volume (V₂): ?

Since we are dealing with an ideal gas, we can calculate the final volume using Boyle's law.

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