Use the formula in terms of half life from the normal exponential functions
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N(t) = N(0) (1/2) ^ (t/thalf) </span>
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N(0) is the original quantity </span>
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N(t) = quantity remaining at time t </span>
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t is the time </span>
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thalf is half life </span>
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1/16 = (1/2)^(t/3.82) </span>
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16 = 2^(t/3.82) </span>
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4 = t/3.82 </span>
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t = 15.28 days
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answer: dispersed from the liquid so cold air can take its place
What they have in common is that they both have the same number of atoms. Hope this helps. :)
Answer:
c) (12×0.9889) + (13×0.01108)
Explanation:
Given data:
Percentage of C-12 = 98.89%
Percentage of C-13 = 1.108%
Atomic mass = ?
Solution:
98.89/100 = 0.9889
1.108/ 100 = 0.01108
Atomic mass = (12×0.9889) + (13×0.01108)
Atomic mass = (11.8668 + 0.144034)
Atomic mass = 12.01084
