What is the standard form of equation of a circle with center at (-2, -3) and passing through the point (-2, 0)?

1 answer:

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Hello :
an equation of the circle Center at the A(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
in this exercice : a = -2 and b =-3 (Center A(-2,-3))
r = AP......(P(-2,0))
r² = (AP)²
r² = (-2+2)² +(-3-0)² = 9
an equation of the circle that satisfies the stated conditions.
Center A(-2,-3) , passing through P(-2, 0) is : (x+2)² +(y+3)² = 9

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Answer:

Step-by-step explanation:

The range is the y values of the function from the least to the greatest. To find it find the furthest point up and down. Draw a horizontal line from the point to the y-axis to identify the y value. Here the function extends from -3 to 6. So the range is $-3\leq y\leq 6$ .