All categories

3 years ago

I need help I'm stuck

Mathematics

2 answers:

Yuliya22 [10]3 years ago

5 0

2/7.
2/7 + 5/7 =1 Just add the numerator if the denominator is the same

Liula [17]3 years ago

5 0

The answer is 2/7
you turn 1 to 7/7 then subtract

You might be interested in

Hi, i need help on these. thank you very much [urgent]

stepladder [879]

$(4y - 3x) \times (4y + 3x)$

$( {11a}^{5} - {b}^{4} ) \times ( {11a}^{5} + {b}^{4} )$

7 0

3 years ago

Geometry help please. Thank you. I picked C but that answer is wrong. What term Describes RT?

Fiesta28 [93]

Answer:

angle bisector

Step-by-step explanation:

RT is an angle bisector of the triangle

6 0

2 years ago

Can anyone help me with this math problem plss?

gulaghasi [49]

Answer:

14/24 ( simplified = 7/12)

Step-by-step explanation:

to find this we multiply the fractions 2/3 and 7/8

7/8 x 2/3 = 14/24

So Shannon ate 14/24 lb

You can simplify to = 7/12

3 0

2 years ago

I need helpppppppppppp

____ [38]

Answer:

The first one is 36 i think and the second is 28 i think

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

What is ∛1728. Then multiplied by ∛14903

NeTakaya

Cube root of 1728 is 12 and on multiplying it by cube root of 14903 we get 295.306.

<u>Solution: </u>

Need to calculate $\sqrt[3]{1728}$ and then multiply the result by $\sqrt[3]{14903}$

Let us first evaluate $\sqrt[3]{1728}$

$\Rightarrow \sqrt[3]{1728}=\sqrt[3]{12 \times 12 \times 12}=12$

As need to multiply 12 by $\sqrt[3]{14903}$

$\Rightarrow 12 \times \sqrt[3]{14903}$

On solving $\sqrt[3]{14903}$ , we get

$\sqrt[3]{14903}=24.608$

$\Rightarrow 12 \times \sqrt[3]{14903}=12 \times 24.608=295.306$

Hence cube root of 1728 is 12 and on multiplying it by cube root of 14903 we get 295.306.

8 0

3 years ago