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3 years ago

Robert plans to make a box-and-whisker plot of the following set of data.

Mathematics

2 answers:

Stella [2.4K]3 years ago

7 0

Answer:

answer

C.lower quartile: 18; median: 27; upper quartile: 38

Step-by-step explanation:

Lunna [17]3 years ago

4 0

Answer:

lower quartile: 18; median: 27; upper quartile: 38

Step-by-step explanation:

The given set of data is

27, 14, 46, 38, 32, 18, 21

Arrange this set of data in numeric order

14,18,21,27,32,38,46

The given set of data has 7 numbers which is odd.

Median in the middle value. The middle value of the data is fourth value which is 27.

Hence, median = 27

Now, the first half of the set of data is

14,18,21

Middle value = 18

Hence, lower quartile = 18

The second half is 32,38,46

Middle value = 38

Hence, uper quartile = 38

Thus, the correct option is

lower quartile: 18; median: 27; upper quartile: 38

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She has to score at least 86 on her fifth test.

Further explanation:

We will use the average formula to find the fifth value.

Given

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The formula for average is:

$x=\frac{Sum\ of\ values}{Total\ number\ of\ values}\\Here,\\n=5\\So,\\x=\frac{x_1+x_2+x_3+x_4+x_5}{5}\\Putting\ values\\80=\frac{81+73+84+76+x_5}{5}$

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She has to score at least 86 on her fifth test.

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The given parameters are:

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