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2 years ago

Robert plans to make a box-and-whisker plot of the following set of data.

Mathematics

2 answers:

Stella [2.4K]2 years ago

7 0

Answer:

answer

C.lower quartile: 18; median: 27; upper quartile: 38

Step-by-step explanation:

Lunna [17]2 years ago

4 0

Answer:

lower quartile: 18; median: 27; upper quartile: 38

Step-by-step explanation:

The given set of data is

27, 14, 46, 38, 32, 18, 21

Arrange this set of data in numeric order

14,18,21,27,32,38,46

The given set of data has 7 numbers which is odd.

Median in the middle value. The middle value of the data is fourth value which is 27.

Hence, median = 27

Now, the first half of the set of data is

14,18,21

Middle value = 18

Hence, lower quartile = 18

The second half is 32,38,46

Middle value = 38

Hence, uper quartile = 38

Thus, the correct option is

lower quartile: 18; median: 27; upper quartile: 38

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Step-by-step explanation:

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(x^2y^3) = (xy^a)^b

Rainbow [258]

Answer:

C. $\frac{3}{2}$

Step-by-step explanation:

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$( {x}^{m} )^{n} = {x}^{mn}$

We apply this rule on both sides to get:

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