Question

Your friend is catching a falling basketball after it has passed through the basket. Her hands move straight down while catching the ball. It takes about 0.10 s for the player to lower her hands to stop the ball. Assume the mass of the ball is 0.60 kg, and that the ball has fallen a vertical distance of 1.2 m before reaching the player's hand. Determine the average force that her hands exert on the ball while catching it.

Answer 1

Answer:$F=29 N$    

Explanation:

Given

time t=0.1 s

mass of ball m=0.6 kg

distance moved before coming to stop d=1.2 m

Net Force exerted

$F=\frac{\Delta P}{\Delta t}$

$F=\frac{m\Delta v}{\Delta t}$

$F=\frac{m\sqrt{2gd}}{\Delta t}$

$F=\frac{0.6\cdot \sqrt{2\cdot 9.8\cdot 1.2}}{0.1}$

$F=\frac{0.6\cdot 4.849}{0.1}$

$F=\frac{2.90}{0.1}$

$F=29 N$