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2 years ago

What color will a yellow banana appear when illuminated by yellow light

Physics

1 answer:

Phantasy [73]2 years ago

3 0

Answer:

A yellow banana reflects only yellow light,

Explanation:

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A searchlight is 210 ft from a straight wall. As the beam moves along the wall, the angle between the beam and the perpendicula

Ivenika [448]

Answer:

The length of the beam increasing is 9.64 ft/s.

Explanation:

Given that,

Height = 210 ft

Distance =290 ft

According to figure,

We need to calculate the angle

$\cos\theta=\dfrac{210}{x}$ ....(I)

Put the value of x in the equation

$\cos\theta=\dfrac{210}{290}$

$\cos\theta=\dfrac{21}{29}=0.72$

Now, $\sin\theta=\dfrac{20}{29}$

On differentiate of equation (I)

$-\sin\theta\dfrac{d\theta}{dt}=-\dfrac{-210}{x^2}\dfrac{dx}{dt}$

$\sin\theta=\dfrac{210}{x^2}\dfrac{dx}{dt}$

Put the value in the equation

$\sin\dfrac{20}{29}\times2.0=\dfrac{210}{(290)^2}\dfrac{dx}{dt}$

$\dfrac{dx}{dt}=\sin\dfrac{20}{29}\times2.0\times\dfrac{290^2}{210}$

$\dfrac{dx}{dt}=9.64\ ft/s$

Hence, The length of the beam increasing is 9.64 ft/s.

4 0

3 years ago

An object has a position given by r = [2.0 m + (5.00 m/s)t] i^ + [3.0m−(2.00 m/s2)t2] j^, where all quantities are in SI units.

makkiz [27]

Answer:

Acceleration of the object is $4\ m/s^2$ .

Explanation:

It is given that, the position of the object is given by :

$r=[2\ m+(5\ m/s)t]i+[3\ m-(2\ m/s^2)t^2]j$

Velocity of the object, $v=\dfrac{dr}{dt}$

Acceleration of the object is given by :

$a=\dfrac{d^2r}{dt^2}$

$a=\dfrac{d^2}{dt^2}([2\ m+(5\ m/s)t]i+[3\ m-(2\ m/s^2)t^2]j)$

Using the property of differentiation, we get :

$a=\dfrac{d^2r}{dt^2}=-4\ m/s^2$

So, the magnitude of the acceleration of the object at time t = 2.00 s is $4\ m/s^2$ . Hence, this is the required solution.

5 0

2 years ago

Which is a property of bases?

vesna_86 [32]

Answer:

C. Slippery feel

Explanation:

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2 years ago

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What was the speed of a space shuttle that orbited Earth at an altitude of 1482 km?

gregori [183]

Answer:

v = 7121.3 m/s

Explanation:

As we know that the centripetal force for the space shuttle is due to gravitational force of earth due to which it will rotate in circular path with constant speed

so here we will have

$\frac{mv^2}{r} = \frac{GMm}{r^2}$

here we know that

r = orbital radius = 6370 km + 1482 km

$r = 7.852 \times 10^6 m$

also we know that

$M = 5.97 \times 10^{24} kg$

now we will have

$v^2 = \frac{(6.67 \times 10^{-11})(5.97 \times 10^{24})}{7.852 \times 10^6}$

$v^2 = 5.07 \times 10^7$

$v = 7121.3 m/s$

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3 years ago

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When an object is lifted against the force of gravity it has gravitational potential energy. The energy depends on the object's

USPshnik [31]

The answer is actually True, I just took the test and it was correct.

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3 years ago

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