1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
KiRa [710]
3 years ago
8

How high off the ground is a 5.5 kg object that has a gravitational potential energy of 8500 DE=mah​

Physics
1 answer:
umka21 [38]3 years ago
7 0

Answer:

h = 157.70 meters

Explanation:

Given the following data;

Mass = 5.5 kg

Gravitational potential energy = 8500 Joules

We know that acceleration due to gravity is equal to 9.8 m/s².

To find the height of the object;

Gravitational potential energy (GPE) is an energy possessed by an object or body due to its position above the earth.

Mathematically, gravitational potential energy is given by the formula;

G.P.E = mgh

Where;

G.P.E represents potential energy measured in Joules.

m represents the mass of an object.

g represents acceleration due to gravity measured in meters per seconds square.

h represents the height measured in meters.

Substituting into the formula, we have;

8500 = 5.5*9.8*h

8500 = 53.9h

h = 8500/53.9

h = 157.70 m

You might be interested in
In a classical carnival ride, patrons stand against the wall in a cylindrically shaped room. Once the room gets spinning fast en
g100num [7]

Answer:

- the speed of a person "stuck" to the wall is 14.8 m/s

- the normal force of the wall on a rider of m=54kg is 1851 N

- the minimum coefficient of friction needed between the wall and the person is 0.29

Explanation:

Given information:

the radius of the cylindrical room, R = 6.4 m

the room spin with frequency, ω =  22.1 rev/minutes = 22.1 \frac{2\pi }{60} = 2.31 rad/s

mass of rider, m = 54 kg

the speed of a person "stuck" to the wall

v = ω R

  = 2.31 x 6.4

  = 14.8 m/s

the normal force of the wall on a rider

F = m a

a  = ω^2 R

   =  \frac{v^{2} }{R^{2} } R

   = \frac{v^{2} }{R}

F = \frac{mv^{2} }{R}

  = \frac{(54)(14.8)^{2} }{6.4}

  = 1851 N

the minimum coefficient of friction needed between the wall and the person

F(friction) = μ N

W =  μ N

m g =  μ \frac{mv^{2} }{R}

g = μ \frac{v^{2} }{R}

μ = \frac{gR}{v^{2} }

  = \frac{(9.8) (6.4)}{14.8^{2} }

  = 0.29

5 0
3 years ago
Both the X- and Y-components of a vector are doubled. Which of the following describes what happens to the resulting Vector?
Aliun [14]

Answer: C. Magnitude increases by 2

Explanation:

7 0
4 years ago
CCL4 is Non polar and NH3 is Polar? Why?​
lys-0071 [83]

Answer:

  • CCL4 is non polar cause' they are equal covalent bonds between carbon and chlorine.
  • The electronegativity difference between hydrogen and nitrogen is about .9 which is a pretty polar bond. So each N-H bond is definitely polar. But NH3 is also asymmetrical .
6 0
2 years ago
Brainlists please help<br><br>on the coner opposite of 8n is 5n​
atroni [7]

Answer:

resultant force=16N→(TOWARDS THE DIRECTION OF 8N)

Explanation:

resultant force=8N+13N-5N

                        =16N→(TOWARDS THE DIRECTION OF 8N)

6 0
3 years ago
The U. S. Navy is helping these Congolese soldiers conduct an inspection of vehicles, looking mostly for car bombs. They can ins
Mashutka [201]
A flat mirror; reflection
6 0
3 years ago
Read 2 more answers
Other questions:
  • A wrestler weighs in for the first match on the moon. will the athleates wiegh more or less on the moon than he will on the eart
    5·1 answer
  • A light ray incident on a block of glass makes an incident angle of 50.0° with the normal to the surface. The refracted ray in t
    5·1 answer
  • Calculate the centripetal force exerted on the Earth by the Sun. Assume that the period of revolution for the Earth is 365.25 da
    11·1 answer
  • Explain how a metamorphic rock that has a pattern of bands was formed
    15·1 answer
  • A ball of mass 0.1kg is thrown vertically upwards with an initial velocityof 80 m/s. calculate the pontential energy (i) half wa
    9·1 answer
  • A 50.0-kg crate is being pulled along a horizontal smooth surface. The pulling force is 10.0 n and is directed 20.0° above the h
    10·1 answer
  • ¿Por qué se sostiene que dicho modelo de negociación colectiva tendió a favorecer la
    8·1 answer
  • What kind of force are you using when you squish a marshmallow?
    14·2 answers
  • Brittle- would break when struck with force *<br> A-Metal<br> B-Nonmetal<br> C-Metalloid
    13·2 answers
  • Dsfhfdskjhfdkshjkfdhskjdfhkjshjkfhsdkjf
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!