Answer:
Explanation:
Given a parallel plate capacitor of
Area=A
Distance apart =d
Potential difference, =V
If the distance is reduce to d/2
What is p.d
We know that
Q=CV
Then,
V=Q/C
Then this shows that the voltage is inversely proportional to the capacitance
Therefore,
V∝1/C
So, VC=K
Now, the capacitance of a parallel plate capacitor is given as
C= εA/d
When the distance apart is d
Then,
C1=εA/d
When the distance is half d/2
C2= εA/(d/2)
C2= 2εA/d
Then, applying
VC=K
V1 is voltage of the full capacitor V1=V
V2 is the required voltage let say V'
Then,
V1C1=V2C2
V × εA/d=V' × 2εA/d
VεA/d = 2V'εA/d
Then the εA/d cancels on both sides and remains
V=2V'
Then, V'=V/2
The potential difference is half when the distance between the parallel plate capacitor was reduce to d/2
Here it is. It was too much to type on a phone....
Answer:
Density=mass/volume 40 divided by 8 =5
Newton’s second law states that force is the product of
mass and acceleration. This is expressed mathematically as:
F = m * a
Where F = force, m = mass, a = acceleration
Since in the given problem, the force is constant or same
force is acting upon two objects. Therefore we can simply equate the expression
m * a of the 2 objects.
m1 * a1 = m2 * a2
Where m1 = 2 kg, a1 = 38 m/s^2, m2 = 19 kg. Therefore
finding for a2:
2 kg * 38 m/s^2 = 19 kg * a2
<span>a2 = 4 m/s^2 (ANSWER)</span>
Answer:
The net outward force is exerted on a square window of the house is
.
Explanation:
Given that,
Pressure = 1.02 atm
External air pressure = 0.910 atm
Distance = 2.03 m
We need to calculate the net outward force
Using formula of force

Where, P = pressure
F = force
A = area
Put the value into the formula


Hence, The net outward force is exerted on a square window of the house is
.