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KiRa [710]
3 years ago
8

How high off the ground is a 5.5 kg object that has a gravitational potential energy of 8500 DE=mah​

Physics
1 answer:
umka21 [38]3 years ago
7 0

Answer:

h = 157.70 meters

Explanation:

Given the following data;

Mass = 5.5 kg

Gravitational potential energy = 8500 Joules

We know that acceleration due to gravity is equal to 9.8 m/s².

To find the height of the object;

Gravitational potential energy (GPE) is an energy possessed by an object or body due to its position above the earth.

Mathematically, gravitational potential energy is given by the formula;

G.P.E = mgh

Where;

G.P.E represents potential energy measured in Joules.

m represents the mass of an object.

g represents acceleration due to gravity measured in meters per seconds square.

h represents the height measured in meters.

Substituting into the formula, we have;

8500 = 5.5*9.8*h

8500 = 53.9h

h = 8500/53.9

h = 157.70 m

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In a semiclassical model of the hydrogen atom, the electron orbits the proton at a distance of 0.053 nm. Part A What is the elec
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Answer with Explanation:

We are given that

r=0.053 nm=0.053\times 10^{-9} m

1 nm=10^{-9} m

Charge on proton,q=1.6\times 10^{-19} C

a.We have to find the electric  potential of the proton at the position of the electron.

We know that the electric potential

V=\frac{kq}{r}

Where k=9\times 10^9

V=\frac{9\times 10^9\times 1.6\times 10^{-19}}{0.053\times 10^{-9}}

V=27.17 V

B.Potential energy of electron,U=\frac{kq_e q_p}{r}

Where

q_e=-1.6\times 10^{-19} c=Charge on electron

q_p=q=1.6\times 10^{-19} C=Charge on proton

Using the formula

U=\frac{9\times 10^9\times (-1.6\times 10^{-19}\times 1.6\times 10^{-19}}{0.053\times 10^{-9}}

U=-4.35\times 10^{-18} J

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When you drop a paper clip, why doesn't it fall toward you instead of toward<br> Earth?
svetoff [14.1K]
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4025.05m +20.0m +0.050004m
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Fill in a T/F answer for each statement below. If false, correct the statement to make it true.:
grandymaker [24]

Answer:

Explanation:

Let's answer these statements

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           v = c / n

.3) True. The frequency creates a forced oscillation, whereby the atoms re-emit at the same incident frequency

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3 0
3 years ago
A hot air balloon must be designed to support a basket, cords, and one person for a total payload weight of 1300 N plus the addi
RSB [31]

Answer:

r = 4.44 m

Explanation:

 

For this exercise we use the Archimedes principle, which states that the buoyant force is equal to the weight of the dislodged fluid

         B = ρ g V

Now let's use Newton's equilibrium relationship

         B - W = 0

         B = W

The weight of the system is the weight of the man and his accessories (W₁) plus the material weight of the ball (W)

         σ = W / A

         W = σ A

The area of ​​a sphere is

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Let's replace

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If we use the ideal gas equation

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    P = ρ RT

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    r² 4π (P/3RT  r - σ) = W₁

Let's replace the values

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     r² (11.81 r -0.060) = 13000 / 4pi

     r² (11.81 r - 0.060) = 1034.51

As the independent term is very small we can despise it, to find the solution

       r = 4.44 m

3 0
3 years ago
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