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vovangra [49]
3 years ago
6

Climate models are computer simulations of all the complex interactions of the atmosphere, oceans, land surface, ice and biosphe

re. They account for the incoming radiation from the sun and the radiation emitted back out to space. To be able to provide reliable climate simulations and predictions, climate models must be based on the laws of physics and chemistry --
-
True
OR
False --
Physics
1 answer:
Nady [450]3 years ago
8 0
Answer: False

Sorry if this is wrong I’m not positive this answer is right but you can still try it. :)
You might be interested in
The specific heat of copper is 0.385 J/g·°C. What equation would you use to calculate the amount of heat needed to raise the tem
andrew11 [14]

Answer: Q = m c ΔT

Explanation:

Amount of heat required to raise the temperature of an object is give by the equation:

Q = m c ΔT

Where, m is the mass of the object, c is the specific heat and ΔT is the rise in temperature.

It is given that the specific heat of copper is c = .385 J/g°C

Mass of copper, m = 0.90 g

Change in temperature, ΔT = 26°C - 9°C = 17°C

Then amount of heat required to raise the temperature of given amount of copper is:

Q = m c ΔT ⇒ Q = 0.90 g × .385 J/g°C × 17°C = 5.89 J

Thus, 5.89 J is needed to raise the temperature of 0.90 g of copper from 9°C to 26°C.

7 0
4 years ago
A 16 foot ladder is leaning against a wall. If the top of the ladder slides down the wall at a rate of 3 feet per second, how fa
JulsSmile [24]

Answer:

11.625

Explanation:

L = length of the ladder = 16 ft

v_{y} = rate at which top of ladder slides down = - 3 ft/s

v_{x} = rate at which bottom of ladder slides

y = distance of the top of ladder from the ground

x = distance of bottom of ladder from wall = 4 ft

Using Pythagorean theorem

L² = x² + y²

16² = 4² + y²

y = 15.5 ft

Also using Pythagorean theorem

L² = x² + y²

Taking derivative both side relative to "t"

0 = 2x\frac{\mathrm{d} x}{\mathrm{d} t} + 2y\frac{\mathrm{d} y}{\mathrm{d} t}

0 = x v_{x} + y v_{y}

0 = 4 v_{x} + (15.5) (- 3)

v_{x} = 11.625 ft/s

7 0
3 years ago
The pressure of a gas (relative to vacuum) inside a rigid container at 0 °C is:
gizmo_the_mogwai [7]

The pressure of a gas inside a rigid container at 0 °C will not be zero, but will somewhat be less than it would be at 25 °C.

<h3>Temperature and pressure of gases</h3>

According to Charle's law of gases, the pressure of a gas is directly proportional to its temperature. This is based on the condition that the volume of the gas does not change.

Thus, for a gas inside a rigid container, the pressure at 0 °C may not be zero. However, the pressure will be less than it would be if the temperature were to be 25 °C.

More on Charle's law can be found here: brainly.com/question/16927784

#SPJ1

3 0
2 years ago
How does the mass of an object affect its acceleration?
gizmo_the_mogwai [7]

Answer:

the mass + the 1 constant g-force = the speed without adding air resistance

Explanation:

osmium it the most tightly packed alloy in the world so for that it will have a faster acceleration

5 0
3 years ago
A 100-g block slides back and forth on a frictionless surface between two springs, as shown in Fig. 7.18. The left-hand spring h
Andreyy89

(a) Energy is conserved at every point in the block's motion, so the potential energy P stored in the first spring at its maximum compression is the same as is stored in the second spring.

The total work performed on the block by the first spring is

W = -1/2 (110 N/m) (0.21 m²) = -2.4255 J

The work performed by the second spring is the same, so

W = -1/2 (240 N/m) x²

Solve for x :

x² = -2W/(240 N/m) = 0.0202125 m²

x ≈ 0.14 m = 14 cm

(b) By the work-energy theorem, the total work performed by either spring on the block as the spring is compressed is equal to the change in the block's kinetic energy. The restoring force of the spring is the only force involved. At maximum compression, the block has zero velocity, while its kinetic energy and hence speed is maximum just as it comes into contact with either spring.

W = 0 - K

W = -1/2 (0.10 kg) v²

v² = -2W/(0.10 kg) = 48.51 m²/s²

v ≈ 7.0 m/s

7 0
3 years ago
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