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Minchanka [31]
3 years ago
14

Which of the following equations represents an unbalanced neutralization reaction equation? a) HBr + Ca(OH)2 → CaBr2 + H2O b) SO

2 + H2O → H2SO3 c) NaCl + H2O → HCl + NaOH d) Na + H2O → NaOH + H2
Chemistry
2 answers:
scZoUnD [109]3 years ago
8 0

HBr + Ca(OH)2 → CaBr2 + H2O as you can see that amount of oxygen on both sides is not the same.

katrin2010 [14]3 years ago
4 0
<span>When you have to balance an equation it means that you have to balance both parts of equation so that the numbers of each elements will have the same amount. According to this rule, it is quite easy to distinguish unbalanced reaction, and the answer is a) HBr + Ca(OH)2 → CaBr2 + H2O as you can see that amount of oxygen on both sides is not the same.</span>
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A particular chemical reaction is exergonic. What can you say about the relationship between the reactants and the products in t
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Answer:

Products have a lower total Gibbs free energy in comparison with the reagents total Gibbs free energy.

Explanation:

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Exergonic chemical reactions are those that the overall Gibbs free energy is negative, it means that the products have a lower total Gibbs free energy, turning out into a spontaneous chemical reaction. Such reactions are thermodynamically possible under standard conditions and they usually release heat.

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7 0
3 years ago
25 mL of 0.10 M aqueous acetic acid is titrated with 0.10 M NaOH(aq). What is the pH after 30 mL of NaOH have been added?
weeeeeb [17]

Answer:

pH = 11.95≈12

Explanation:

Remember  the reaction among aqueous acetic acid (CH_3COOH) and aqueous sodium hydroxide (NaOH)

CH_3COOH + NaOH ->  CH_3COONa + H_2O

First step. Need to know how much moles of the substances are present

0.1 \frac{mol NaOH}{L} * 0.030 L = 0.003 mol NaOH[tex]0.1 \frac{mol CH_3COOH}{L} * 0.025 L= 0.0025 mol CH_3COOHSecond step. Know wich substance is in excess.0.0025 mol CH_3COOH * [tex]1 mol NaOH/ 1 mol CH_3COOH = 0.0025 mol NaOH

0.003 mol NaOH * 1 mol CH_3COOH/ 1 mol NaOH = 0.003 mol CH_3COOH[/tex]

NaOH is in excess. Now, how much?

0.003 mole NaOH - 0.0025 mole NaOH = 0.0005 mole NaOH

Then, that amount in excess would be responsable for the pH.

Third step. Know the pH

Remember that pH= -log[H+]

According to the dissociation of water equilibrium

Kw=[H+]*[OH-]= 10^(-14)

The dissociation of NaOH is

NaOH -> Na^{+} + OH^{-}

Now, concentration of OH^{-}[/tex] would be given for the excess of NaOH.

[OH-]= 0.0005 mole / 0.055 L = 0.00909 M

Careful: we have to use the total volumen

Les us to calculate pH

pH= -log [H+]\\pH= -log \frac{K_w}{[OH-]} \\pH= 11.95

6 0
3 years ago
HELP.....From the information presented in the activity series of metals below (4 metals included), answer the following questio
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Answer:

a)there would be no reaction

Explanation:

The activity series of metals has many functions. The one applicable to this problem is that it can be used to determine whether a reaction will occur or not. Also, based on the positions of metals in the series, we can know how reactive a metal is compared to another.

In a single displacement reaction, a metal replaces another metal based on their position on the activity series. Metals that are higher in the series are generally more reactive than others below them and so will displace them.

 

Would aluminum replace magnesium to form a new compound or would there be no reaction?

Magnesium is higher than aluminum in the activity series. Therefore it is more reactive than aluminum. No reaction will occur.

6 0
2 years ago
Which scientist determined the charge of the electron?.
Alexus [3.1K]

Answer:

J.J. Thomson

Explanation:

3 0
2 years ago
Describe what is happening in this chemical equation: Al2(SiO3)3 + NaOH → Na(SiO3)3 + Al2OH Please Help ASAP
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Answer:

Double replacement reaction

Explanation:

This is what is known as a double replacement reaction. The two parts of each molecule separate and recombine to form two new compounds. For instance, Al_2(SiO_3)_3 separates into Al_2 and (SiO_3)_3, while NaOH separates into Na and OH, and then they recombine with the other compound.

Hope this helps!

7 0
3 years ago
Read 2 more answers
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