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kirza4 [7]
3 years ago
6

For each solution, determine the p-values for each ion indicated. A solution that is 0.493 M in NaCl and 0.314 M in NH 4 Cl .

Chemistry
1 answer:
miss Akunina [59]3 years ago
7 0

Complete Question:

Ions to calculate the p-values: Na⁺, Cl⁻, and NH₄⁺

Answer:

pNa = 0.307

pCl = 0.093

pNH₄ = 0.503

Explanation:

The p-value is calculated by the antilog of the concentration of the substance of interest. For example, pH = -log[H⁺]. Thus, first, let's find the ions concentration.

Both substances are salts that solubilize completely, thus, by the solution reactions:

NaCl → Na⁺ + Cl⁻

NH₄Cl → NH₄⁺ + Cl⁻

So, for both reactions the stoichiometry is 1:1:1 and the concentration of the ions is equal to the concentration of the salts.

[Na⁺] = 0.493 M

[Cl⁻] = 0.493 + 0.314 = 0.807 M

[NH₄⁺] = 0.314 M

The p-values are:

pNa = -log[Na⁺] = -log(0.493) = 0.307

pCl = -log[Cl⁻] = -log(0.807) = 0.093

pNH₄ = -log[NH₄⁺] = -log(0.314) = 0.503

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4 0
3 years ago
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In the compound cah2 calcium has an oxidation number of 2+ and hydrogen has an oxidation number of
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<span>    (+2) + 2 x a = 0 </span>

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7 0
3 years ago
A balloon contains 11.1 g of nitrogen monoxide gas (NO). how many molecules are in the balloon?
grandymaker [24]

The number of molecules that are in balloon are = 2.227 x10^23 molecules

<h3> calculation</h3>

calculate the number of moles of NO

moles = mass/molar mass

molar mass  of NO = 14+ 16 = 30 g/mol

moles is therefore=  11.1 g/30g/mol= 0.37 moles

by use of Avogadro's constant that is

                                     1 mole= 6.02 x10^23  molecules

                                          0.37 =? molecules

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4 0
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A stock solution of ammonia in water is 28 wt% NH3. The Formal Weight (FW) of NH3 is 17.03 g/mol). The solution density at room
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Answer:

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28 wt% is a type of concentration that indicates that 28 g of ammonia is contained in 100 g of solution.

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You need to consider that, when you have density's data it is always referred to solution:

Mass of solution is 100 g, let's find out the volume

0.90 g/mL = 100 g /V

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mol/L = M → molarity a sort of concentration that indicates the moles of solute in 1L of solution

4 0
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