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GenaCL600 [577]
3 years ago
15

Radon-222 is a radioactive gas with a half-life of 3.82 days. How long would it take for fifteen-sixteenths of a sample of radon

-222 to decay?
15.28 days
30.56 days
45.84 days
49.66 days
Chemistry
1 answer:
Fittoniya [83]3 years ago
8 0
Use the formula in terms of half life from the normal exponential functions 
<span>
N(t) = N(0) (1/2) ^ (t/thalf) </span>
<span>
N(0) is the original quantity </span>
<span>
N(t) = quantity remaining at time t </span>
<span>
t is the time </span>
<span>

thalf is half life </span>
<span>
1/16 = (1/2)^(t/3.82) </span>
<span>
16 = 2^(t/3.82) </span>
<span>
4 = t/3.82 </span>
<span>
t = 15.28 days

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
</span>
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gulaghasi [49]
<h3>Answer:</h3>

3.38 × 10²⁴ molecules CO₂

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 5.61 moles CO₂

[Solve] molecules CO₂

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                      \displaystyle 5.61 \ mooles \ CO_2(\frac{6.022 \cdot 10^{23} \ molecules \ CO_2}{1 \ mol \ CO_2})
  2. [DA] Multiply/Divide [Cancel out units]:                                                          \displaystyle 3.37834 \cdot 10^{24} \ molecules \ CO_2

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

3.37834 × 10²⁴ molecules CO₂ ≈ 3.38 × 10²⁴ molecules CO₂

6 0
3 years ago
(Please help, ASAP) How many grams are in 3.45x10^23 atoms of P?
Daniel [21]

one mole of P weights about 31 grams

in one mole there are 6.022*10^23 atoms

we use the rule of threes

6.022*10^23atoms......weight..........31 grams

3.45*10^23 atoms.........weight...........x grams

x=(3.45*10^23*31)/6.022*10^23

x=106.95/6.022=<u><em>17.76 grams</em></u>

5 0
2 years ago
Student perfotms a Benedict's test on an unknown substance. He adds reagent(the chemical required to make a color change), and n
elixir [45]

Answer:

Reducing sugars are absent

Explanation:

Benedict's solution is an substance used in testing sugars. It is mixture of sodium carbonate, sodium citrate and copper(II) sulfate pentahydrate. It can be used instead of Fehling's solution in testing for the presence of reducing sugars.

Reducing sugars contain the -CHO group. If there is no colour change after the addition of Benedict's solution, then we can conclude that reducing sugars are absent.

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3 years ago
A good hypothesis must be which of the following?
yanalaym [24]
Testable, that is always required for a hypothesis. Otherwise, how can you prove it?
8 0
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What is the correct ratio of the atoms of the two elements present in a sample of the compound copper chloride, CuCl2?
Aleonysh [2.5K]

The correct ratio of the atoms of the two elements in the sample of copper chloride compound would be 1:2.

<h3>Atoms of elements</h3>

Copper chloride has a chemical formula, CuCl_2.

Thus, an atom of copper, Cu, combines with 2 atoms of chlorine, Cl.

The 2 chlorine atoms are recipients of an electron each from the copper atom which happens to have 2 electrons in its outermost valence shell.

Therefore, the ratio of copper to chlorine atoms in the compound is 1:2.

More on atoms of elements can be found here: brainly.com/question/15173445

#SPJ1

8 0
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