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GenaCL600 [577]
3 years ago
15

Radon-222 is a radioactive gas with a half-life of 3.82 days. How long would it take for fifteen-sixteenths of a sample of radon

-222 to decay?
15.28 days
30.56 days
45.84 days
49.66 days
Chemistry
1 answer:
Fittoniya [83]3 years ago
8 0
Use the formula in terms of half life from the normal exponential functions 
<span>
N(t) = N(0) (1/2) ^ (t/thalf) </span>
<span>
N(0) is the original quantity </span>
<span>
N(t) = quantity remaining at time t </span>
<span>
t is the time </span>
<span>

thalf is half life </span>
<span>
1/16 = (1/2)^(t/3.82) </span>
<span>
16 = 2^(t/3.82) </span>
<span>
4 = t/3.82 </span>
<span>
t = 15.28 days

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
</span>
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