Given that,
Mass of the object, m = 1 kg
It moves in a circle of radius 0.5 m with a speed of 5 m/s
To find,
The direction of the acceleration.
Solution,
Whenever an object moves in a circular path, the only force that acts on its is centripetal force which is given by the formula as follows :
The centripetal acceleration acts in the direction of force. It acts along the radius of the circular path. In this figure, the direction of the acceleration is shown at point d.
Answer:
Answered
Explanation:
u = 1.75 m/s
h = 15 m
Now, for the magnitude of velocity when hitting the deck
Using third equation of motion
v^2 - 1.75^2 = 2×9.8×15
v = 17.15 m/s
the velocity of sandal when it hits the deck is 17.15 m/s this the velocity of sandal relative to the ship
b) velocity relative to a stationary observer on shore
=
=17.23 m/s
To a person aboard the ship, they see the sandal land directly below the release point. A stationary observer on the outside sees the same thing, except the fact that the landing point has translated to the south.