All categories

2 years ago

In this graph, what is the displacement of the particle in the last teo seconds?

Physics

1 answer:

White raven [17]2 years ago

6 0

Answer: B

Explanation:

Displacement is a vector quantity. it is the distance covered in a specific direction.

Whereas, Velocity = displacement/time

Make displacement the subject of formula

Displacement = velocity × time

From the graph, velocity is constant which is equal to 1 m/s

Displacement in the last two seconds will be velocity multiply by 2. Since time = 2s. Therefore,

Displacement = 1 × 2 = 2 m

So, the particle displacement in the last two seconds will be 2 metres

You might be interested in

A 20-kg barrel is rolled up a 20-m ramp to the back of a truck whose floor is 5.0 m above the ground. What work is done in loadi

oee [108]

The angle of inclination is calculated using sin function,

sin θ = 5 m / 20 m = 0.25

θ = 14.4775°

The net force exerted is then calculated:
F net = m g sin θ = 20 * 9.8 * 0.25

F net = 49N

Work is product of net force and distance:
W = F net * d = 49 * 20

Work = 980 J

4 0

3 years ago

Which of the following best describes the location of the

marshall27 [118]

Answer:

The mantle exists above the crust of the earth

8 0

2 years ago

I DO NOT WANT LINKES OR …………..

il63 [147K]

1st B is correct option

2nd D is correct option

4 0

2 years ago

Read 2 more answers

1)the car's engine power is 44000W. Explain this number in a physical sense

Ratling [72]

Answer:

1) It expresses the rate (top speed) at which it can move with time.

2) P = 20 W

3) h = 18 km

Explanation:

1) Power is the rate of transfer of energy.

⇒ Power = $\frac{Energy(or workdone)}{Time}$

i.e P = $\frac{E}{t}$

Thus a car's engine power is 44000W implies that the engine of the car can propel the car at this rate. This expresses the rate (top speed) at which it can move with time.

2) m = 400g = 0.4 kg

t = 20 s

h = 100m

g = 10 m/ $s^{2}$

P = $\frac{mgh}{t}$

= $\frac{0.4*10*100}{20}$

= $\frac{400}{20}$

P = 20 W

3) u = 600 m/s

g = 10 m/ $s^{2}$

From the third equation of free fall,

$V^{2}$ = $U^{2}$ - 2gh

V is the final velocity, U is the initial velocity, h is the height.

0 = $(600)^{2}$ - 2 x 10 x h

0 = 360000 - 20h

20h = 360000

h = $\frac{360000}{20}$

= 18000

h = 18 km

The maximum height of the bullet would be 18 km.

3 0

2 years ago

Is it true or not true

maria [59]

Answer:

true

Explanation:

6 0

3 years ago