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kari74 [83]
3 years ago
9

In this graph, what is the displacement of the particle in the last teo seconds?

Physics
1 answer:
White raven [17]3 years ago
6 0

Answer: B

Explanation:

Displacement is a vector quantity. it is the distance covered in a specific direction.

Whereas, Velocity = displacement/time

Make displacement the subject of formula

Displacement = velocity × time

From the graph, velocity is constant which is equal to 1 m/s

Displacement in the last two seconds will be velocity multiply by 2. Since time = 2s. Therefore,

Displacement = 1 × 2 = 2 m

So, the particle displacement in the last two seconds will be 2 metres

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Suppose a 4.0-kg projectile is launched vertically with a speed of 8.0 m/s. What is the maximum height the projectile reaches?
eduard

Answer:

h = 3.3 m (Look at the explanation below, please)

Explanation:

This question has to do with kinetic and potential energy. At the beginning (time of launch), there is no potential energy- we assume it starts from the ground. There, is, however, kinetic energy

Kinetic energy = \frac{1}{2}mv^{2}

Plug in the numbers = \frac{1}{2}(4.0)(8^{2})

Solve = 2(64) = 128 J

Now, since we know that the mechanical energy of a system always remains constant in the absence of outside forces (there is no outside force here), we can deduce that the kinetic energy at the bottom is equal to the potential energy at the top. Look at the diagram I have attached.

Potential energy = mgh = (4.0)(9.8)(h) = 39.2(h)

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128 J = 39.2h

h = 3.26 m

h= 3.3 m (because of significant figures)

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3 years ago
Acceleration toward the center of a curved path is called
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Answer:

Centripetal acceleration.

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It is calculated through following formula

a=v^2/r

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b!!!! did it help? :)))

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What is most responsible for the uneven heating of the air in the atmosphere?
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Can someone help me with this question
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Explanation:

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