Ask question

Ask question

All categories

2 years ago

6

Since 1924, 4 out of 22 Winter Olympics have been held in the U.S. In simplest form, what fraction of the Winter Olympics from 1

924 on have not been held in the U.S.?

1 answer:

Dafna11 [192]2 years ago

6 0

The fraction of winter Olympics that hasn't been held in the U. S is 9/11

You might be interested in

Find all the factor pairs for 84 and complete the equations.

VMariaS [17]

1. 84 = 1 x 84

2. 84 = 2 x 42

3. 84 = 3 x 28

4. 84 = 4 x 21

5. 84 = 6 x 14

6. 85 = 7 x 12

Hope this helps!

5 0

3 years ago

Which is the graph of the linear inequality y<3x+1

Varvara68 [4.7K]

Answer:

This is in the form y=mx+b . m is the slope and b is the y-intercept. In this case, the slope is 3 and the y-intercept is −1 .

5 0

3 years ago

The sum of two consecutive odd integers is 20 less than four times the smaller of the two integers. Which of the following equat

erik [133]

Mmmmmdghdjebbdghsjbdjbf

6 0

2 years ago

Write the following as a root in radical form 2^-4/5

erastovalidia [21]

Answer:

Given that:

=2^(-4/5)

This means that 2 is the base and -4/5 is the exponent.

To change it in radical form:

firstly the denominator would be written with radical sign
Then the negative sign with 4 will be removed by inverting the base.
Then the fraction will be simplified according to the exponent (power)
All the steps are performed below:

$=\sqrt[5]{2^{-4} } \\=\sqrt[5]{1/2^4}\\ =\sqrt[5]{1/16}$

i hope it will help you!

6 0

2 years ago

The average diameter of sand dollars on a certain island is 4.00 centimeters with a standard deviation of 0.60 centimeters. If 1

blagie [28]

Answer:

0.8413 is the required probability.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 4.00 centimeters

Standard Deviation, σ = 0.60 centimeters

Sample size, n = 16

We are given that the distribution of average diameter is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

Standard error due to sampling =

$=\dfrac{\sigma}{\sqrt{n}} = \dfrac{0.60}{\sqrt{16}} = 0.15$

P(diameter of sample is more than 3.85 centimeter)

P(x > 3.85)

$P( x > 3.85) = P( z > \displaystyle\frac{3.85 - 4}{0.15}) = P(z > -1)$

$= 1 - P(z \leq -1)$

Calculation the value from standard normal z table, we have,

$P(x > 3.85) = 1 -0.1587 = 0.8413$

0.8413 is the probability that the the average diameter of sample of 16 sand dollars is more than 3.85 centimeters.

4 0

3 years ago