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Studentka2010 [4]
3 years ago
5

What is 0.000028474 in scientific notation

Chemistry
2 answers:
Luda [366]3 years ago
8 0

Answer:

2.8474 * 10^-5.

Explanation:

There are 5 digits after the decimal point and up to and including the 2 so the exponent is -5.

antiseptic1488 [7]3 years ago
6 0

Answer:

2.8474 \:  \times  \:  {10}^{ - 5}

this the solution

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The number of electrons. The valence (outer) shell is particularly important.
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Explanation:

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50 POINTS!!!
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7 0
3 years ago
At 25∘C, the decomposition of dinitrogen pentoxide, N2O5(g), into NO2(g) and O2(g) follows first-order kinetics with k=3.4×10−5
Annette [7]

Answer:

4600s

Explanation:

2N_{2}O_{5}(g) - - -> 4NO_{2}(g) +O_{2}

For a first order reaction the rate of reaction just depends on the concentration of one specie [B] and it’s expressed as:

-\frac{d[B]}{dt}=k[B] - - -  -\frac{d[B]}{[B]}=k*dt

If we have an ideal gas in an isothermal (T=constant) and isocoric (v=constant) process.

PV=nRT we can say that P = n so we can express the reaction order as a function of the Partial pressure of one component.  

-\frac{d[P(B)]}{P(B)}=k*dt  

-\frac{d[P(N_{2}O_{5})]}{P(N_{2}O_{5})}=k*dt

Integrating we get:

\int\limits^p \,-\frac{d[P(N_{2}O_{5})]}{P(N_{2}O_{5})}=\int\limits^ t k*dt

-(ln[P(N_{2}O_{5})]-ln[P(N_{2}O_{5})_{o})])=k(t_{2}-t_{1})

Clearing for t2:

\frac{-(ln[P(N_{2}O_{5})]-ln[P(N_{2}O_{5})_{o})])}{k}+t_{1}=t_{2}

ln[P(N_{2}O_{5})]=ln(650)=6.4769

ln[P(N_{2}O_{5})_{o}]=ln(760)=6.6333

t_{2}=\frac{-(6.4769-6.6333)}{3.4*10^{-5}}+0= 4598.414s

4 0
3 years ago
The molar mass of NaCl is 58.44 g/mol. What is the molarity of a solution that
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3:00m cu of the current in electrical engineering and electrical toques
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