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3 years ago

PLEASE ANSWER ASAP! DOUBLE CHECK THE ANSWER!

1 answer:

7 0

I believe the answer would be C, unbalanced.
Since the forces are in opposite directions, and aren't the same size, the answer would be unbalanced.

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What is the concentration in mass percent of a solution prepared from 50.0g nacl and 150.0g of water?

otez555 [7]

M(NaCl)=50.0 g
m(H₂O)=150.0 g

m(solution)=m(NaCl)+m(H₂O)

w(NaCl)=100m(NaCl)/m(solution)=100m(NaCl)/{m(NaCl)+m(H₂O)}

w(NaCl)=100*50.0/(50.0+150.0)=25%

3 0

3 years ago

Identify six elements common to organic compounds.

valentinak56 [21]

Carbon and hydrogen are present in all
nitrogen is common
sulphur in proteins is common
oxygen is common in ethanoic acids
phosphorus is common for phosphate sugars

hope that helps

4 0

3 years ago

3) What are the three types of sedimentary rocks?

astraxan [27]

Answer:

clastic, organic, and chemical

8 0

3 years ago

the value of kc for the following reaction is 0.630 at 409 K N2O4(g) --> 2NO2(g) if a reaction vessel at that temperature int

stealth61 [152]

Answer: The concentration of nitrogen dioxide at equilibrium is 0.063 M

Explanation:

We are given:

Initial concentration of nitrogen dioxide = 0.0250 M

Initial concentration of dinitrogen tetraoxide = 0.0250 M

For the given chemical equation:

$N_2O_4(g)\rightleftharpoons 2NO_2(g)$

Initial: 0.025 0.025

At eqllm: 0.025-x 0.025+2x

The expression of $K_c$ for above equation follows:

$K_c=\frac{[NO_2]^2}{[N_2O_4]}$

We are given:

$K_c=0.630$

Putting values in above expression, we get:

$0.630=\frac{(0.025+2x)^2}{(0.025-x)}\\\\x=-0.2013,0.019$

Neglecting the negative value of 'x', because concentration cannot be negative

So, equilibrium concentration of nitrogen dioxide = (0.025 + 2x) = [0.025 + 2(0.019)] = 0.063 M

Hence, the concentration of nitrogen dioxide at equilibrium is 0.063 M

6 0

3 years ago

A cool, yellow-orange flame is used to heat the crucible. Would this affect the mass of the crucible? If so, how?

s2008m [1.1K]

Answer:

yes

Explanation:

Usually, it would not affect the crucible, but depending on the temperature of the flame the enamel of the crucible may begin to melt and stick to the metal object being used to handle the crucible. This tiny amount that is melted off can cause very small changes in the original mass of the crucible, which although it is almost unnoticeable it is still there. Therefore, the answer to this question would be yes.

5 0

3 years ago