A mixture of sand and table salt cam be separated by filtration because the substances in the mixture differ in

1 answer:

6 0

A mixture of sand and table salt can be separated by filtration because the substances in the mixture differ in solubility. Because sand and table salt have a different ability to dissolve they can easily be separated. What can be done to separate this mixture is to add water to it and stir it thoroughly. The salt will easily dissolve in water while the sand will stay insoluble. The filtration of this mixture will result in salt being drained off with water while only the sand will remain.

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Use the periodic table to select which type of bond is present and which of the listed properties is most likely for each substa

jenyasd209 [6]

Answer:

A = Metallic Bond

B = Strong bonding, strong conductor, high melting and boiling points

Explanation:

Since the bond is between two metals (located in groups 11 and 12), they would experience metallic bonding. Metallically bonded molecules have high melting and boiling points due to the strength of the metallic bond. They also experience strong electrical current due to the there delocalized electrons.

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3 years ago

The average bond energy (enthalpy) for a C=C double bond is 614 kJ/mol and that of a C−C single bond is 348 kJ/mol. Estimate the

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Answer:

4.42x10⁻¹⁹ J/molecule

Explanation:

At a double bond, there's sigma and a pi bond, and at a single bond, there's only a sigma bond. Thus, if the energy to break both sigma and pi is 614 kJ/mol, and the energy to break only the sigma bond is 348 kJ/mol, the energy to break only the pi bond is:

E = 614 - 348 = 266 kJ/mol

Knowing that 1 kJ = 1000 J, E = 266,000 J/mol

By Avogadro's number, 1 mol = 6.02x10²³ molecules, thus:

E = 266,000 J/mol * 1mol/6.02x10²³ molecules

E = 4.42x10⁻¹⁹ J/molecule

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otez555 [7]

According to Graham's Law ," the rates of effusion or diffusion of two gases are inversely proportional to the square root of their molecular masses at given pressure and temperature".

r₁ / r₂ =   $\sqrt{M2 / M1}$ ---- (1)

r₁ = Rate of effusion of He

r₂ = Rate of Effusion of O₃

M₁ = Molecular Mass of He = 4 g/mol

M₂ = Molecular Mass of O₃ = 48 g/mol

Putting values in eq. 1,

r₁ / r₂ =   $\sqrt{48 / 4}$

r₁ / r₂ =   $\sqrt{12}$

r₁ / r₂ = 3.46

Result:
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