Ionic compounds contain both cations and anions in a ratio that results in no net electrical charge
Answer:
b. hydride shift from C-3 to C-2.
Explanation:
Markovnikov's rule states that *in the addition of a protic acid HX or other polar reagent to an asymmetric alkene, the acid hydrogen (H) or electropositive part gets attached to the carbon with more hydrogen substituents, and the halide (X) group or electronegative part gets attached to the carbon with more alkyl substituents* (wikipedia).
This rule implies that the hydrogen of HBr will be attached to C-1 and the carbocation will be on C-2. Remember that the order of stability of carbocations is tertiary > secondary > primary > methyl. A hydride shift can yield a tertiary carbocation.
C-3 is a tertiary carbon atom. If the hydride on carbon 3 shifts to carbon 2, a tertiary and more stable carbocation is formed. This accounts for the major product in the reaction.
Polonium has an atomic number of 84 meaning it has 84 protons. Usually, this means there would also be 84 electrons in a normal element. A -3 charge means that there are 3 more negative electrons that positive protons so the overall number of electrons would be 87.
It allows your blood to carry oxygen. #TeamAlvaxic