140 tickets were sold to public and 260 tickets were sold to students
<h3><u>Solution:</u></h3>
Let "p" be the number of tickets sold to public
Let "s" be the number of tickets sold to students
Cost of one ticket sold to public = $ 8.00
Cost of one ticket sold to student = $ 3.00
There were a total of 400 tickets sold
number of tickets sold to public + number of tickets sold to students = 400
p + s = 400 -------- eqn 1
Making a total revenue of 1900.00$
number of tickets sold to public x Cost of one ticket sold to public + number of tickets sold to students x Cost of one ticket sold to student = 1900.00
![p \times 8.00 + s \times 3.00 = 1900.00](https://tex.z-dn.net/?f=p%20%5Ctimes%208.00%20%2B%20s%20%5Ctimes%203.00%20%3D%201900.00)
8p + 3s = 1900 ------ eqn 2
<em><u>Let us solve eqn 1 and eqn 2 to find values of "p" and "s"</u></em>
Multiply eqn 1 by 3
3p + 3s = 1200 ---- eqn 3
Subtract eqn 3 from eqn 2
8p + 3s = 1900
3p + 3s = 1200
(-) ------------------
5p = 700
<h3>p = 140</h3>
Substitute p = 140 in eqn 1
p + s = 400
140 + s = 400
<h3>s = 260</h3>
Thus 140 tickets were sold to public and 260 tickets were sold to students