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Daniel [21]
2 years ago
10

When talking on a phone, the voice is transformed into electrical energy. This energy passes over wires or is transmitted throug

h the air. Into what kind of energy does the speaker in the phone on the other end change the electrical energy?
Chemistry
2 answers:
Art [367]2 years ago
5 0
It transferred from electrical to sound.
dedylja [7]2 years ago
3 0

The speaker changes the electrical energy into sound energy.

Explanation: "Speakers in a phone convert electrical energy into sound energy, so it can be heard by the person speaking from the other phone."

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What is the electron configuration of the element in group 14 and period 4 of the periodic table
AlekseyPX

Answer: The first three elements i.e., C, Si & Ge form mostly the covalent compounds.

...

SALIENT FEATURES OF GROUP 14 (CARBON FAMILY) ELEMENTS.

Period 4

Element Germanium

Symbol Ge

Atomic number (Z) 32

Electronic configuration [Ar] 3d10 4s2 4p2

Explanation:

7 0
2 years ago
What is Heterogeneous? And an example. What is Homogeneous? And an example. I just need those, thanks
Sedbober [7]
Homo means same
Hetero means different
Geneous means DNA
So homogeneous is same DNA
and heterogenous is different DNA
7 0
3 years ago
The process in which organisms grow and replace worn-out cells is called: A. Cell regeneration B. Cell division C. Mitosis D. Bo
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7 0
3 years ago
When 0.25 moles of NH3 are produced according to the reaction below, how many moles of H2 must have reacted?
marissa [1.9K]

Answer:

Explanation:

by stoichiometry

nNH3/2=nH2/3

0.25/2=nH2/3

nH2=0.25×3/2

nH2=0.375 mol

so its 0.38 mol

6 0
3 years ago
Read 2 more answers
If volumes are additive and 253 mL of 0.19 M potassium bromide is mixed with 441 mL of a potassium dichromate solution to give a
Alexxx [7]

Answer:

The concentration of the Potassium Dichromate solution is 0.611 M

Explanation:

First of all, we need to understand that in the final solution we'll have potassium ions coming from KBr and also K2Cr2O7, so we state the dissociation equations of both compounds:

KBr (aq) → K+ (aq) + Br- (aq)

K2Cr2O7 (aq) → 2K+ (aq) + Cr2O7 2- (aq)

According to these balanced equations when 1 mole of KBr dissociates, it generates 1 mole of potassium ions. Following the same thought, when 1 mole of K2Cr2O7 dissociates, we obtain 2 moles of potassium ions instead.

Having said that, we calculate the moles of potassium ions coming from the KBr solution:

0.19 M KBr: this means that we have 0.19 moles of KBr in 1000 mL solution. So:

1000 mL solution ----- 0.19 moles of KBr

253 mL solution ----- x = 0.04807 moles of KBr

As we said before, 1 mole of KBr will contribute with 1 mole of K+, so at the moment we have 0.04807 moles of K+.

Now, we are told that the final concentration of K+ is 0.846 M. This means we have 0.846 moles of K+ in 1000 mL solution. Considering that volumes are additive, we calculate the amount of K+ moles we have in the final volume solution (441 mL + 253 mL = 694 mL):

1000 mL solution ----- 0.846 moles K+

694 mL solution ----- x = 0.587124 moles K+

This is the final quantity of potassium ion moles we have present once we mixed the KBr and K2Cr2O7 solutions. Because we already know the amount of K+ moles that were added with the KBr solution (0.04807 moles), we can calculate the contribution corresponding to K2Cr2O7:

0.587124 final K+ moles - 0.04807 K+ moles from KBr = 0.539054 K+ moles from K2Cr2O7

If we go back and take a look a the chemical reactions, we can see that 1 mole of K2Cr2O7 dissociates into 2 moles of K+ ions, so:

2 K+ moles ----- 1 K2Cr2O7 mole

0.539054 K+ moles ---- x = 0.269527 K2Cr2O7 moles

Now this quantity of potassium dichromate moles came from the respective  solution, that is 441 mL, so we calculate the amount of them that would be present in 1000 mL to determine de molar concentration:

441 mL ----- 0.269527 K2Cr2O7 moles

1000 mL ----- x = 0.6112 K2Cr2O7 moles = 0.6112 M

6 0
3 years ago
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