How do I find the number of atoms in grams of an element?

How is energy in a washing machine being utilised and wasted?

7nadin3 [17]

Answer:

It depends on whether the setting is hot or cold .-.

Explanation:

8 0

2 years ago

Read 2 more answers

3

atroni [7]

Answer:

(1) atomic numbers

Explanation:

The observed regularities in the properties of the elements on the periodic table are periodic functions of their atomic numbers.

Atomic number is the number of protons in an atom.
The periodic law states that "the properties of elements are a periodic function of their atomic number".
Elements on the periodic table are arranged based on the atomic numbers they contain.
The number of positively charged particles in an atom is the atomic number.

6 0

3 years ago

For alkyl halides used in SN1 and SN2 mechanisms, rank the leaving groups in order of reaction rate. You are currently in a rank

Alex777 [14]

Answer:

Iodide> Bromide > chloride > flouride

Explanation:

During a nucleophilic substitution reaction, a nucleophilie replaces another in a molecule.

This process may occur via an ionic mechanism (SN1) or via a concerted mechanism (SN2).

In either case, the ease of departure of the leaving group is determined by the nature of the C-X bond. The stronger the C-X bond, the worse the leaving group will be in nucleophilic substitution. The order of strength of C-X bond is F>Cl>Br>I.

Hence, iodine displays the weakest C-X bond strength and it is thus, a very good leaving group in nucleophillic substitution while fluorine displays a very high C-X bond strength hence it is a bad leaving group in nucleophilic substitution.

Therefore, the ease of the use of halide ions as leaving groups follows the trend; Iodide> Bromide > chloride > flouride

4 0

3 years ago

Consider the balanced reaction: 4Ga(s) + 3O2(g)⟶ 2Ga2O3(s)

Paha777 [63]

First we need to find the number of moles that 43.9g of gallium metal is. We can do this by finding the molar weight of gallium and cross-multiplying to cancel out units:

$\frac{1mole}{69.723g}*\frac{43.9g}{1}=0.63mol_{Ga}$

So we are dealing with 0.63 moles of gallium metal.

We can take from the balanced equation that 4 moles of gallium metal will react completely with 3 moles of oxygen gas. We can take this ratio and make a proportion to find the amount of oxygen gas, in moles, that will react completely with 0.63 moles of gallium metal:

$\frac{4moles_{Ga}}{3moles_{O_{2}}} =\frac{0.63moles_{Ga}}{xmoles_{O_{2}}}$

Cross multiply and solve for x:

$4x=1.89$

$x=0.47moles_{O{2}}$

So now we know that 0.47 moles of oxygen gas will react with 43.9g of gallium metal.

5 0

3 years ago

In a laboratory experiment the reaction of 3.0 mol of H2 with 2.0 mol of I2 produced 1.0 mole of HI. Determine theoratical yield

Kobotan [32]

Answer:

Theoretical yield of HI is 512 g.

The percent yield for this reaction is 25%.

Explanation:

$H_2+I_2\rightarrow 2HI$

Moles of hydrogen gas = 3.0 moles

Moles of iodine gas = 2.0 moles

According to reaction 1 mol of hydrogen gas reacts with 1 mol of iodine gas.

Then 3.0 moles of hydrogen gas reacts with 3.0 mol of iodine gas. But there are 2.0 moles of iodine gas. Hence,Iodine is a limiting reagent. The production of HI will depend upon iodine gas moles.

According to reaction , 1 mol of iodine gas gives 2 moles of HI.

Then 2 moles of iodine gas will give:

$\frac{2}{1}\times 2 mol=2 mol$ of HI