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3 years ago

Use the investigation set up below to write a conclusion statement for what is happening to the liquid. Choose the best answer.

Chemistry

1 answer:

jeka57 [31]3 years ago

8 0

D is the answer. Just look at the picture on your test ❤

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Briefly explain why the bulk temperature of the water remains low (at room temperature)

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If the humidity of the room is low, the water that contacts the air directly could evaporate and takes some energy from the bulk thus decreasing its temperature steadily. This allows the water to have a lower temperature.

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3 years ago

Evan watches the weather report on the news. The announcer states that an air mass formed over a tropical ocean is moving into t

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2 years ago

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Please help my teacher has like given up

NikAS [45]

Answer:

24.47 L

Explanation:

Using the general gas law equation:

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

n = number of moles (mol)

R = 0.0821 Latm/molK

T = temperature (K)

According to the provided information in this question,

P = 1.0 atm

V = ?

n = 1 mol

T = 25°C = 25 + 273 = 298K

Using PV = nRT

V = nRT ÷ P

V = 1 × 0.0821 × 298 ÷ 1

V = 24.465 ÷ 1

V = 24.465

V = 24.47 L

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3 years ago

What are the names of the two magnetic poles?

gizmo_the_mogwai [7]

What are the names of the two magnetic poles?

Ur answer is

North and South

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2 years ago

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Determine the value of the equilibrium constant, Kgoal, for the reactionN2(g)+H2O(g)⇌NO(g)+12N2H4(g), Kgoal=?by making use of th

Black_prince [1.1K]

Answer:

$K_{goal}=1.793*10^{-33}$

Explanation:

N2(g)+O2(g)⇌2NO(g), $K_1 = 4.10*10^{-31}$

N2(g)+2H2(g)⇌N2H4(g), $K_2 = 7.40*10^{-26}$

2H2O(g)⇌2H2(g)+O2(g), $K_3 = 1.06*10^{-10}$

If we add above reaction we will get:

2N2(g)+2H2O(g)⇌2NO(g)+N2H4(g) Eq (1)

Equilibrium constant for Eq (1) is $K_1*K_3*K_3$

Divide Eq (1) by 2, it will become:

N2(g)+H2O(g)⇌NO(g)+1/2N2H4(g) Eq (2)

Equilibrium constant for Eq (2) is $(K_1*K_3*K_3)^{1/2}$

$Equilibrium constant =K_{goal}= (K_1*K_2*K_3)^{1/2}\\K_{goal}= (4.10*10^{-31} *7.40*10^{-26}*1.06*10^{-10})^{1/2}\\K_{goal}=1.793*10^{-33}$

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3 years ago