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3 years ago

Elaborate on the difference in natural occurrences between fission and fusion reactions.

1 answer:

5 0

Fission is the division of one atom into two, and fusion is the combination of two lighter atoms into larger one. They are opposing processes and therefore very different.

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Carbon dioxide is returned to the atmosphere primarily by the

Mandarinka [93]

Answer:c or d

Explanation:

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3 years ago

Read 2 more answers

How many atoms are<br> below?<br> C6H1206

Vinvika [58]

Answer:

24 atoms

Explanation:

6 Carbon atoms

12 Hydrogen atoms

6 Oxygen atoms

8 0

4 years ago

When dinitrogen pentaoxide, a white solid, is heated, it decomposes to produce nitrogen dioxide gas and

AysviL [449]

9.5314 L is the volume of nitrogen dioxide formed at 103.25 kPa and 22.75 °C.

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

Given data:

Oxygen produced - 1.618 gram

Decomposition of $N_2O_5$ takes place.

Find - Amount of $NO_2$ produced.

The decomposition reaction is as follows -

$2N_2O_5$ --> $4NO_2 + O_2$

Moles of $O_2$ gas = $\frac{1.6}{16}$ =0.1 moles.

1 mole of $O_2$ is produced from 2 moles of dinitrogen pentoxide

0.1 mole of $O_2$ will be produced from = 0.2 moles.

Now, 2 moles of dinitrogen pentoxide produce 4 moles of $NO_2$

$NO_2$ produced will be - 0.4 moles.

Weight of $NO_2$ produced - 0.4 X 46

Weight of $NO_2$ produced - 18.4 gram

Thus, grams of $NO_2$ produced are 18.4

Now calculate the volume of $NO_2$

Given data are:

P=103.25 kPa =1.01899827 atm

T= 22.75 °C +273 = 295.75 K

n=0.4 moles

V=?

R= 0.0821 liter·atm/mol·K

Putting the value in PV=nRT

V = $\frac{nRT}{P}$

V = $\frac{0.4 \;moles \;X \;0.0821\; liter\;atm/\;mol \;K X \;295.75 \;K}{1.01899827 atm}$

V= 9.5314 L

Hence, 9.5314 L is the volume of nitrogen dioxide formed at 103.25 kPa and 22.75 °C.

Learn more about the ideal gas equation here:

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8 0

2 years ago

In experiment 1, how many moles of benzoic acid are present? how many moles of sodium bicarbonate are contained in 1 ml of a 10%

nexus9112 [7]

First, let us calculate the moles of solute or sodium bicarbonate is in the 1 ml solution.

<span>moles = 1 mL * (1 g / 9 mL) = 0.11 moles</span>

The molar mass of sodium bicarbonate is 84 g/mol, therefore the mass is:

mass = 0.11 moles * 84 g/mol

6 0

4 years ago

The process of the classifying living thing is

jok3333 [9.3K]

Answer:

D. all of these

Explanation:

In the classification of organisms, they are placed into groups which they appropriately fit into.

All the choices given correctly shows the process of classifying organisms. This aspect of biology is described as taxonomy.

Based on characteristics of organisms, they are put into the same groups
Also, we can identify the related family and genus in which a discovered organism can be put into.
They phylogenetic relationship between organisms are important for classification.

7 0

3 years ago