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motikmotik
2 years ago
13

What are ways in controlling soil applicable in your community​

Chemistry
1 answer:
kiruha [24]2 years ago
5 0

Answer:

Some methods of controlling soil erosion.

1) Planting Vegetation. This method involves planting crops with deep roots that can hold the soil in place. ...

2)Contour Farming. ...

3)Applying Mulches. ...

4)Avoiding Overgrazing. ...

5)Reforestation. ...

6)Use Plastic Sheeting. ...

7)Applying Terraseeding Method

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If the molecule C6H12 does not contain a double bond, and there are no branches in it, what will its structure look like?
NARA [144]
I have attached a photo of the structure. 
You can get better at solving problems like this by practicing a lot! 




5 0
4 years ago
Anybody know chemistry Grahams law ?
sukhopar [10]
There is two different types but i’ll just do both meanings just incase.

Graham's Law of Diffusion: the rate of diffusion of one gas through another is inversely proportional to the square root of the density of the gas.

Graham's Law of Effusion: the rate of effusion of a gas is inversely proportional to the square root of the density of the gas.

hopes this helps..!
7 0
3 years ago
C12H22011+1202-->12CO2+11H20
kogti [31]

Answer:

0.185moles

Explanation:

Given parameters:

Volume of O₂  = 49.8L

Unknown:

Number of moles of sucrose required  = ?

Solution:

We can assume that the reaction takes place at standard temperature and pressure.

From this, we can find the number of moles of oxygen that reacted and extrapolate to that of sucrose.

Chemical equation;

           C₁₂H₂₂0₁₁  +  120₂   →   12CO₂   +   11H₂0

Number moles  = \frac{volume of gas}{22.4}   at STP

Number of moles of oxygen gas = \frac{49.8}{22.4}   = 2.22moles

           12 moles of oxygen gas combines with  1 mole of sucrose

       2.22 moles of oxygen gas will combine with \frac{2.22}{12}   = 0.185moles

4 0
4 years ago
A sample of an unknown solid is found to have a volume of 24.3 cm3 and a mass of
blondinia [14]
<h2>Answer:  8.93 g/cm³ </h2>

<h3>Explanation: </h3>

Density = mass ÷ volume  

           = 217.0 g ÷ 24.3 cm³  

           = 8.93 g/cm³

∴ the unknown sample of mass 217.0 grams and volume of 24.3 cm³ has a density of 8.93 g/cm³.

5 0
2 years ago
What property can be used to separate oil from milk?
Usimov [2.4K]

Answer:

Density oil will float

Explanation:

3 0
3 years ago
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