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motikmotik
2 years ago
13

What are ways in controlling soil applicable in your community​

Chemistry
1 answer:
kiruha [24]2 years ago
5 0

Answer:

Some methods of controlling soil erosion.

1) Planting Vegetation. This method involves planting crops with deep roots that can hold the soil in place. ...

2)Contour Farming. ...

3)Applying Mulches. ...

4)Avoiding Overgrazing. ...

5)Reforestation. ...

6)Use Plastic Sheeting. ...

7)Applying Terraseeding Method

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The mass fractions of a mixture of gases are 15 percent nitrogen, 5 percent helium, 60 percent methane, and 20 percent ethane wi
Setler79 [48]

Answer:

Explanation:

mass fraction N₂ : He : CH₄ : C₂H₆ : : 15 : 5 : 60 : 20

mole fraction  N₂ : He : CH₄ : C₂H₆ : : 15/28 : 5/4 : 60/16 : 20/30

mole fraction  N₂ : He : CH₄ : C₂H₆ : : .5357  : 1.25 : 3.75 : .67

Total mole fractions = .5357 + 1.25 + 3.75 + 0.67 = 6.2057

mole fraction of N₂ =  .5357 / 6.2057 = .0877

mole fraction of He = 1.25 / 6.2057 = .20

mole fraction of CH₄ = 3.75 / 6.2057 = .6043

mole fraction of C₂H₆ = .67 / 6.2057 = .108

Partial pressure = total pressure x mole fraction

Partial pressure of N₂ = 1200 kPa  x .0877 = 105.24 kPa

Partial pressure of He = 1200 kPa  x .20  = 240 kPa

Partial pressure of CH₄ = 1200 kPa  x  .6043  = 725.16 kPa

Partial pressure of C₂H₆ = 1200 kPa  x .108    = 129.6 kPa

6 0
3 years ago
Which species is most vulnerable to extinction raccoon or mountain gorilla
777dan777 [17]
Mountain Gorilla’s are more vulnerable to extinction because they are endangered due to habitat loss, diseases, poaching, ect.
6 0
3 years ago
Read 2 more answers
Observation and assessment are most effective when
Artist 52 [7]
I think the answer is A. Hope that helped :)
6 0
3 years ago
The formation of aluminum chloride can be described by the balanced chemical equation.
ikadub [295]

Answer:this is hard tho-

Explanation:

4 0
2 years ago
The gaseous product of a reaction is collected in a 25.0L container at 27.0 C. The pressure in the container is 3.0atm and the g
NeX [460]

Answer: The molar mass of the gas is 31.6 g/mol

Explanation:

According to ideal gas equation:

PV=nRT

P = pressure of gas = 3.0 atm

V = Volume of gas = 25.0 L

n = number of moles  = ?

R = gas constant =0.0821Latm/Kmol

T =temperature =27.0^0C=(27.0+273)K=300K

n=\frac{PV}{RT}

n=\frac{3.0atm\times 25.0L}{0.0821 L atm/K mol\times 300K}=3.04moles

Moles =\frac{\text {given mass}}{\text {Molar mass}}

3.04=\frac{96.0g}{\text {Molar mass}}

{\text {Molar mass}}=31.6g/mol

The molar mass of the gas is 31.6 g/mol

4 0
3 years ago
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