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nalin [4]
2 years ago
11

I need a break down on how to do my home work step by step. Ex. (8)(-5)+(-7)(3)

Mathematics
1 answer:
FinnZ [79.3K]2 years ago
5 0
Let's break this problem down and solve it step-by-step.

STEP-BY-STEP SOLUTION:

Keep in mind the following:

Two positives together or two negatives together = positive

One positive and one negative together = negative

Okay, now let's begin solving the problem.

= ( 8 ) ( - 5 ) + ( - 7 ) ( 3 )

First we will multiply the brackets together.

= ( - 40 ) + ( - 21 )

Next we will remove the brackets and change the positive ( + ) and negative ( - ) symbol into just a negative symbol, as a positive and negative always equals a negative as stated previously.

= - 40 - 21

Now we will simply subtract 21 from - 40 to achieve our final answer.

= - 61

Hope this helps! :)
Have a lovely day! <3
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Since it went 8 floors in 6 seconds you divide. 8/6 is 1.333 or 1 1/3 floors per second. Hope this helps.
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3 years ago
Find the product of (x − 3)2.
jeyben [28]
(x - 3)^2

(x - 3) * (x - 3)
x^2 - 3x
+ -3x + 9
x^2 - 6x + 9
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2 years ago
Mr. Reciprocal started walking as his New Year's resolution. He calculated that he can walk 1/2 mile in 1/4 of an hour. What is
kondaur [170]
2 hours per hour cause 1/4=15 min 1/2 times 4 equals 2 so  2 miles per hour
4 0
3 years ago
solve the system of equations by finding the reduced row-echelon form of the augmented matrix for the system of equations. x-2y+
Alekssandra [29.7K]

Answer:

x = -5, y = -6, z = -3

Step-by-step explanation:

Given the system of three equations:

\left\{\begin{array}{l}x-2y+3z=-2\\6x+2y+2z=-48\\x+4y+3z=-38\end{array}\right.

Write the augmented matrix for the system of equations

\left(\begin{array}{ccccc}1&-2&3&|&-2\\6&2&2&|&-48\\1&4&3&|&-38\end{array}\right)

Find the reduced row-echelon form of the augmented matrix for the system of equations:

\left(\begin{array}{ccccc}1&-2&3&|&-2\\6&2&2&|&-48\\1&4&3&|&-38\end{array}\right)\sim \left(\begin{array}{ccccc}1&-2&3&|&-2\\0&-14&16&|&36\\0&-6&0&|&36\end{array}\right)\sim \left(\begin{array}{ccccc}1&3&-2&|&-2\\0&16&-14&|&36\\0&0&-6&|&36\end{array}\right)

Thus, the system of three equations is

\left\{\begin{array}{r}x+3z-2y=-2\\16z-14y=36\\-6y=36\end{array}\right.

From the last equation:

y=-6

Substitute it into the second equation:

16z-14\cdot (-6)=36\\ \\16z=36-84\\ \\16z=-48\\ \\z=-3

Substitute y = -6 and z = -3 into the first equation:

x+3\cdot (-3)-2\cdot (-6)=-2\\ \\x=-2+9-12\\ \\x=-5

7 0
3 years ago
Find the sum of deviation of all observations of the data 5, 8, 10, 15, 22 from their mean.​
ivann1987 [24]

Answer:

the sum of deviation of all observations of the data 5, 8, 10, 15, 22 from their mean. =26

Step-by-step explanation:

Mean=sum of observation/ No. of observation

={5+8+ 10+ 15 + 22}/5

=60/5=12

Sum of deviations

= |5- 12| + |8 – 12| + |10- 12| + |15- 12| + |22-12|

= 7+4+2+ 3+ 10

= 26

3 0
2 years ago
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