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2 years ago

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What is atomic number?

1 answer:

vladimir2022 [97]2 years ago

3 0

Atomic number is the total number of electrons present in an atom

Or you can say like

atomic number is the number of electron and proton present in an atom

Both can be used

Hope it helps : )

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When a person pushes off a wall with 15N of force,how much force does the wall push back

aivan3 [116]

Newton's third law of motion states that for every action force, there is an equal and opposite reaction force so that means that the wall is pushing you with the same amount of force that you put on it.

5 0

3 years ago

Please help!! 20 points!! Posted this previously and forgot to change it to 20 points but it is now

spayn [35]

Answer:

0.571 mol

Explanation:

Given data:

Number of moles of NaHCO₃ = 0.571 mol

Number of moles of CO₂ produced = ?

Solution:

Chemical equation:

NaHCO₃ + C₃H₆O₃ → CO₂ + C₃H₅NaO₃ + H₂O

Now we will compare the moles of CO₂ with NaHCO₃ from balance chemical equation.

NaHCO₃ : CO₂

1 : 1

0.571 : 0.571

So number of moles of CO₂ produced are 0.571.

3 0

2 years ago

Read 2 more answers

Balance this equation K+b2o3=k2o+b

AVprozaik [17]

Answer:

Explanation:

2K and 2b

5 0

2 years ago

I NEED HELP<br>Only the smallest particles of soil can be displaced by suspension because

Sidana [21]

Answer:

It's because they are easily carried by the wind.

<u><em>Hope I helped :)</em></u>

6 0

3 years ago

Read 2 more answers

A compound is found to consist of 34.5% sodium, 16.4% boron, and 48.6% oxygen. What is the empirical formula?

NARA [144]

Answer: The empirical formula is $NaBO_2$

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given:

Mass of Na= 34.5 g

Mass of B= 16.4 g

Mass of O = 48.6 g

Step 1 : convert given masses into moles.

Moles of Na = $\frac{\text{ given mass of Na}}{\text{ molar mass of Na}}= \frac{34.5g}{23g/mole}=1.5moles$

Moles of B = $\frac{\text{ given mass of B}}{\text{ molar mass of B}}= \frac{16.4g}{11g/mole}=1.5moles$

Moles of O = $\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{48.6g}{16g/mole}=3moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For Na = $\frac{1.5}{1.5}=1$

For B = $\frac{1.5}{1.5}=1$

For O = $\frac{3}{1.5}=2$

The ratio of Na: B: O= 1: 1: 2

Hence the empirical formula is $NaBO_2$

7 0

2 years ago