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Sladkaya [172]
3 years ago
6

What is the name of the group that contains elements that are difficult to extract from nature?

Chemistry
1 answer:
Alex787 [66]3 years ago
4 0

Answer:

Alkali metals

Explanation:

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The atom in a sample of an element must contain nuclei with the same number of?
slava [35]
Hey there! 

Answer: Protons 

The atom in a sample of an element must contain nuclei with the same number of protons. If the protons change in number, then the element will modify as well. 

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3 years ago
How many particles are in the nucleus of an atom of fluorine-19?
svetoff [14.1K]

Answer:

9 protons, 10 neutrons, and 9 electrons.

Explanation:

The particles of the nucleus of an atom of Fluorine-19 is

9 protons, 10 neutrons, and 9 electrons.

4 0
2 years ago
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What is the solution to the problem expressed to the correct number of significant figures? 2.13 + 1 = ?
Paha777 [63]

So,

With addition, we the last digit we keep will be the one which is known for both individual values.

We know 2.13 to the hundredths, but we only know 1 to the ones.  Therefore, we will round off in the ones place.

2.13 + 1 = 3.13 (unrounded)

= 3 (rounded)

Hope this helps!

7 0
3 years ago
Name each of the isotope
Alex73 [517]

Answer:

Examples of radioactive isotopes include carbon-14, tritium (hydrogen-3), chlorine-36, uranium-235, and uranium-238.

8 0
2 years ago
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For the reaction 2 H2S(g) D 2 H2 (g) + S2 (g), Kp = 1.5 × 10−5 at 800.0°C. If the initial partial pressures of H2 and S2 in a cl
Usimov [2.4K]

Answer: The approximate equilibrium partial pressure of H_2S is 3.92  atm

Explanation:

Equilibrium constant is the ratio of the concentration of products to the concentration of reactants each term raised to its stochiometric coefficients.

The given balanced equilibrium reaction is,

      2H_2S(g)\rightleftharpoons 2H_2(g)+S_2(g)

K_p=\frac{[H_2]^2\times [S_2]}{[H_2S]^2}

1.5\times 10^{-5}=\frac{[H_2]^2\times [S_2]}{[H_2S]^2}

On reversing the reaction:

     2H_2(g)+S_2(g)\rightleftharpoons 2H_2S(g)

initial pressure  4.00atm    2.00 atm       0

eqm          (4.00-2x)atm      (2.00-x) atm      2x atm

K_p=\frac{[H_2S]^2}{[H_2]^2\times [S_2]}

K_p'=\frac{1}{K_p}=0.67\times 10^5

2H_2(g)+S_2(g)\rightleftharpoons 2H_2S(g)

0.67\times 10^5=\frac{2x]^2}{[4.00-2x]^2\times [2.00-x]}

x=1.96

[H_2S]=2x=2\times 1.96=3.92 atm

Thus approximate equilibrium partial pressure of H_2S is 3.92 atm

3 0
3 years ago
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