Answer:
B) 25
Step-by-step explanation:
Given exponential function:
![f(x)=3(5)^x](https://tex.z-dn.net/?f=f%28x%29%3D3%285%29%5Ex)
The growth factor between
and
is 25.
To find the growth factor between
and ![x=7](https://tex.z-dn.net/?f=x%3D7)
Solution:
The growth factor of an exponential function in the interval
and
is given by :
![G=\frac{f(b)}{f(a)}](https://tex.z-dn.net/?f=G%3D%5Cfrac%7Bf%28b%29%7D%7Bf%28a%29%7D)
We can check this by plugging in the given points.
The growth factor between
and
would be calculated as:
![G=\frac{f(3)}{f(1)}](https://tex.z-dn.net/?f=G%3D%5Cfrac%7Bf%283%29%7D%7Bf%281%29%7D)
![f(3)=3(5)^3](https://tex.z-dn.net/?f=f%283%29%3D3%285%29%5E3)
![f(1)=3(5)^1](https://tex.z-dn.net/?f=f%281%29%3D3%285%29%5E1)
Plugging in values.
![G=\frac{3(5)^3}{3(5)^1}](https://tex.z-dn.net/?f=G%3D%5Cfrac%7B3%285%29%5E3%7D%7B3%285%29%5E1%7D)
(On canceling the common terms)
(Using quotient property of exponents
)
![G=(5)^{2}](https://tex.z-dn.net/?f=G%3D%285%29%5E%7B2%7D)
∴
Similarly the growth factor between
and
would be:
![G=\frac{f(7)}{f(5)}](https://tex.z-dn.net/?f=G%3D%5Cfrac%7Bf%287%29%7D%7Bf%285%29%7D)
![f(7)=3(5)^7](https://tex.z-dn.net/?f=f%287%29%3D3%285%29%5E7)
![f(5)=3(5)^5](https://tex.z-dn.net/?f=f%285%29%3D3%285%29%5E5)
Plugging in values.
![G=\frac{3(5)^7}{3(5)^5}](https://tex.z-dn.net/?f=G%3D%5Cfrac%7B3%285%29%5E7%7D%7B3%285%29%5E5%7D)
(On canceling the common terms)
(Using quotient property of exponents
)
![G=(5)^{2}](https://tex.z-dn.net/?f=G%3D%285%29%5E%7B2%7D)
∴
Thus, the growth factor remains the same which is =25.