-3 (v + 4) = 2v - 37
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The probability that a worker chosen at random works at least 8 hours is Option C: 0.84 approx.
<h3>How to evaluate the probability of a random variable getting at least some fixed value?</h3>Suppose the random variable in consideration be X, and it is discrete.
Then, the probability of X attaining at least 'a' is written as:
It is evaluated as:
The probability distribution of X is:
x f(x) = P(X = x)
6 0.02
7 0.11
8 0.61
9 0.15
10 0.09
Worker working at least 8 hours means X attaining at least 8 as its values.
Thus, probability of a worker chosen at random working 8 hours is
P(X ≥ 8) = P(X = 8) + P(X = 9) +P(X = 10) = 0.85 ≈ 0.84 approx.
By the way, this probability distribution seems incorrect because sum of probabilities doesn't equal to 1.
The probability that a worker chosen at random works at least 8 hours is Option C: 0.84 approx.
Learn more about probability distributions here: