Answers + Explanation:
1. x + 7 =10
if you know some number + 7 is 10, you know that number must be 3.
so, x = 3
the other way you can solve this would be:
x + 7 = 10
subtract 7 from both sides of the equation
x + 7 - 7 = 10 - 7
x = 3
2. Use the same strategy:
x - 8 = -5
add 8 to both sides of the equation
x - 8 + 8 = -5 + 8
x = 3
3. x + 3 = 6
subtract 3 from both sides of the equation
x + 3 - 3 = 6 - 3
x = 3
4. x + 6 = 3
subtract 6 from both sides of the equation
x + 6 - 6 = 3 - 6
x = -3
Answer:
(5y+5) is not right sorry
Step-by-step explanation:
When a quadratic equation ax^2+bx+c has a double root, the discriminant,
D=b^2-4ac=0
Here
a=2,
b=b,
c=18
and
D=b^2-4ac=b^2-4*2*18=0
solve for b
b^2-144=0
=> b= ± sqrt(144)= ± 12
So in order that the given equation has double roots, the possible values of b are ± 12.
Answer:
x = 4y+28
Step-by-step explanation:
x/4 -7 = y
Solve for x
Add 7 to each side
x/4 -7+7 = y+7
x/4 = (y+7)
Multiply each side by 4
x/4*4 = 4(y+7)
x = 4y+28
