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puteri [66]
3 years ago
10

One cubic centimeter of a typical cumulus cloud contains 60 water drops, which have a typical radius of 10 μm. (a) how many cubi

c meters of water are in a cylindrical cumulus cloud of height 3.2 km and radius 1.0 km
Mathematics
1 answer:
Vika [28.1K]3 years ago
4 0

First calculate for the volume of the cylindrical cumulus cloud:

V = π r^2 h

V = π (1.0 km)^2 * 3.2 km

V = 3.2π km^3 = 10.05 km^3

 

We know that there are 60 water drops per cm^3. Therefore:

drops = 10.05 km^3 * (60 drop / cm^3) * (100,000 cm / km)^3

drops = 6.032 x 10^17 drops

 

Calculating for the volume of 1 drop:

Vdrop = (4π/3) r^3

Vdrop = (4π/3) * (10 x 10^-6 m)^3

Vdrop = 4.19 x 10^-15 m^3

 

Hence total volume of the drop is:

Vtotal drops = 6.032 x 10^17 drops * 4.19 x 10^-15 m^3 / drop

<span>Vtotal drops = 2,526.68 m^3</span>

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2 years ago
Aria paid $75,000 for her house. Its property value increased by 2.2% per year. When Aria sold her house after eleven years, how
astra-53 [7]

Answer:

When Aria sold her house after eleven years it worth was <u>$95,300</u>.

Step-by-step explanation:

Given:

Aria paid $75,000 for her house. Its property value increased by 2.2% per year.

Now, to find the worth of Aria house when sold after eleven years.

Let the amount of house after eleven years be x.

Amount Aria paid for her house (A) = $75,000.

Rate of property increased per year (r) = 2.2%.

Time (t) = 11 years.

Now, to get the amount of house after eleven years we put formula:

x=A\times (1+\frac{r}{100})^{11}

x=75000\times (1+\frac{2.2}{100})^{11}

x=75000\times (1+0.022)^{11}

x=75000\times (1.022)^{11}

x=75000\times 1.2704

x=95280.

<em>The amount of house after eleven years to the nearest hundred dollars is $95,300.</em>

Therefore, when Aria sold her house after eleven years it worth was $95,300.

3 0
3 years ago
15. a music concert is organized at a memorial auditorium. the first row of the auditorium has 16 seats, the second row has 24 s
Drupady [299]

The equation for the nth term in the arithmetic sequence is   8n + 8.

The number of people that can be accommodated in the 16th row is 136.

<h3>What is an  arithmetic progression?</h3>

Arithmetic Progression (AP) is a sequence of numbers in order, in which the difference between any two consecutive numbers is a constant value. It is also called Arithmetic Sequence.

Given that,

No. of seats in first row = 16

No. of seats in second row = 24

No. of seats in third row = 32

Total number of rows = 50

It forms an arithmetic progression

First term = a = 16

common difference d = 8

Number of terms, n = 50

(A) The formula for the n th term of an arithmetic progression is given by

Tn = a + (n - 1) d

    = 16 + (n-1) 8

    = 16 + 8n - 8

Tn = 8n + 8

(B) Now,

n = 16

The number of seats in 16 th row is given by

T(16) = 8 x 16 + 8

T(16) = 136 seats

Hence, (A)The equation for the nth term in the arithmetic sequence is   8n + 8. and (B) The number of people that can be accommodated in the 16th row is 136.

To learn more about arithmetic progression  from the given link:

brainly.com/question/24205483

#SPJ4

4 0
1 year ago
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