Which logic function(s) provides a high output in response to only seven low inputs?

A wave of infrared light has a speed of 6m/s and a wave length of 12 m. What is the frequency of this wave?

erastovalidia [21]

Frequency = speed / wavelength

(6 m/s) / (12 m) = 0.5 Hz.

That's not infrared light.
Infrared light waves move about 50 million times faster than that, and they're only about 0.00000007 as long as that.

6 0

3 years ago

2.- Si una cámara fotográfica emite un pulso de sonido para enfocar un objeto, determinar

uranmaximum [27]

Answer:

a. El tiempo de recorrido es $5.882\times 10^{-3}$ segundos para un objeto localizado a un metro de distancia de la cámara fotográfica.

b. El tiempo de recorrido es 0.118 segundos para un objeto localizado a un metro de distancia de la cámara fotográfica.

Explanation:

El sonido es un tipo de onda mecánica, que es un tipo de onda que necesita de un medio material para propagarse. En este caso, entendemos que el sonido se propaga a través del aire atmosférico hasta llegar a su destino y devolverse a rapidez constante. Entonces, podemos estimar el tiempo ( $t$ ), medido en segundos, a partir de la siguiente fórmula:

$t = \frac{2\cdot x_{s}}{v_{s}}$

Donde:

$x_{s}$ - Distancia entre la cámara fotográfica y el objeto, medida en metros.

$v_{s}$ - Rapidez del sonido en el aire atmosférico, medida en metros por segundo.

A continuación, calculamos el tiempo de recorrido:

a. ( $x_{s} = 1\,m$ , $v_{s} = 340\,\frac{m}{s}$ )

$t = \frac{2\cdot (1\,m)}{340\,\frac{m}{s} }$

$t = 5.882\times 10^{-3}\,s$

El tiempo de recorrido es $5.882\times 10^{-3}$ segundos para un objeto localizado a un metro de distancia de la cámara fotográfica.

b. ( $x_{s} = 20\,m$ , $v_{s} = 340\,\frac{m}{s}$ )

$t = \frac{2\cdot (20\,m)}{340\,\frac{m}{s} }$

$t = 0.118\,s$

El tiempo de recorrido es 0.118 segundos para un objeto localizado a un metro de distancia de la cámara fotográfica.

8 0

3 years ago

Why is it important to warm up your muscles before a workout?

slava [35]

Answer: So that you don't have a cramp

Explanation: Muscles can cramp up if not stretched becuase it keeps the muscles flexable and strong and to maintain the range of motion a person has.

7 0

2 years ago

Read 2 more answers

Resistance to the motion of an automobile consists of road friction, which is almost independent of speed, and air drag, which i

Troyanec [42]

Answer:

73.52983 Hp

Explanation:

m = Mass of car = $\dfrac{W}{g}$

W = Weight of car = 12000 N

a = Acceleration = 0.96 m/s²

Velocity of the car

$v=82\times \dfrac{1000}{3600}\\\Rightarrow v=\dfrac{82}{3.6}\\\Rightarrow v=\dfrac{41}{1.8}$

From the question

$F=300+1.8v^2\\\Rightarrow F=300+1.8\times \left(\dfrac{41}{1.8}\right)^2\\\Rightarrow F=1233.88\ N$

Balancing the forces

$\dfrac{P}{v}-1233.88=ma\\\Rightarrow P=(ma+12000)v\\\Rightarrow P=\left(\dfrac{12000}{9.81}\times 0.96+1233.88\right)\dfrac{41}{1.8}\\\Rightarrow P=54853.26055\ W=\dfrac{54853.26055}{746}\\\Rightarrow P=73.52983\ Hp$

The power is 73.52983 Hp

6 0

3 years ago

A fan converts 4.2 kJ of electrical energy to kinetic energy every minute. The power of the fan is...

miss Akunina [59]

The power of the fan is 70 Watt.

<h3 /><h3>What is power?</h3>

Power can be defined as the rate at which energy is used. The S.I unit of power is Watt (W)

The power of the fan can be calculated using the formula below.

<h3>Formula:</h3>

P = E/t.......................... Eqaution 1

<h3>Where:</h3>

P = Power of the fan
E = Energy of the fan
t = time

From the question,

<h3>Given:</h3>

E = 4.2 kJ = 4200 J
t = 1 minutes = 60 seconds.

Substitute these values into equation 1

P = 4200/60
P = 70 Watt.

Hence, The power of the fan is 70 Watt.

Learn more about power here: brainly.com/question/3631756

4 0

2 years ago