How to divide electrons into energy levels?
1 answer:
In Bohr's atomic model, he proposed that the electrons are revolving around the nucleus in their respective orbitals. There are 5 kinds of orbitals: the s, p, d and f orbitals. They differ in their energy level, shape and number of subshells. Each subshell holds two oppositely spinning electrons. The s has 1 subshell, p has 3, d has 5 and f has 7. You arrange the orbitals into energy levels just like how you write them in an electronic configuration.
In the first energy level, you only have one 1s orbital. In the second energy level, you have one 2s and one 2p orbital, the 2p having more energy than 2s. The other levels are shown in the picture.
In the first energy level, you only have one 1s orbital. In the second energy level, you have one 2s and one 2p orbital, the 2p having more energy than 2s. The other levels are shown in the picture.
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Explanation:
The given data is as follows.
F = 3.2 N, m = 18.2 kg,
t = 0.82 sec
(a) Formula for impulse is as follows.
I = Ft =
Ft =
or,
Putting the given values into the above formula as follows.
=
= 0.144 m/s
Therefore, final velocity of the mass if it is initially at rest is 0.144 m/s.
(b) When velocity is 1.85 m/s to the left then, final velocity of the mass will be calculated as follows.
Ft =
or,
=
= -1.705 m/s
Hence, we can conclude that the final velocity of the mass if it is initially moving along the x-axis with a velocity of 1.85 m/s to the left is 1.705 m/s towards the left.
Answer:
Explanation:
So:
(
5
⋅
1
)
+
(
1
⋅
−
4
)
=
(
5
+
1
)
v
5
−
4
=
6
v
v
=
1
6
=
0.17
m
s
