A pet-store supply truck moves at 25.0 m/s north along a highway. inside, a dog moves at 1.75 m/s at an angle of 35.0° east of n orth. what is the velocity of the dog relative to the road
2 answers:
Answer:
26.5 m/s at 2.17° east of north
Explanation:
The velocity component in the north direction:
vᵧ = 25.0 m/s + 1.75 m/s cos 35.0°
vᵧ = 26.4 m/s
The velocity component in the east direction:
vₓ = 1.75 m/s sin 35.0°
vₓ = 1.00 m/s
The magnitude of the velocity is:
v² = vₓ² + vᵧ²
v² = (1.00 m/s)² + (26.4 m/s)²
v = 26.5 m/s
The direction is:
θ = atan(vₓ / vᵧ)
θ = atan(1.00 m/s / 26.4 m/s)
θ = 2.17° east of north
Answer:
15.0 m/s^2
Explanation:
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