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3 years ago

Why do automobiles rust faster in wet climates than in drier climates?

2 answers:

7 0

The water helps the car slide just a little bit if you drive in a wet climate but in a dry climate the car does all the work. for example when you slide across ice with sneakers. on a dry surface you cant slide, but an a icy surface you start but the ice does the rest.

Vinil7 [7]3 years ago

4 0

Automobiles rust faster in wet climate because the chemical reaction between the metal and the iron, oxygen or water breaks down, or oxidizes, the metal causing the appearance of rust.

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Find the work done lifting a 290-pound weight 28 feet in the air.

Nataly [62]

The answer is d.8,120 foot-pounds

6 0

3 years ago

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If a force of 450N pushes a box 4 meters in 2 seconds, how much power was developed?

strojnjashka [21]

Work = (force) x (distance) = (450 N) x (4 m) = 1,800 joules

Power = (work) / (time) = (1,800 joules) / (2 sec) = 900 watts .

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3 years ago

(GIVING BRAINLIEST) do what the following image says.

Delicious77 [7]

Answer:

that pink part that circles around is the pancreas

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3 years ago

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A piece of wood with density of 824 kg/m^3 is tied to the bottom of a pool and the wood does not move. The volume of the wood is

Reil [10]

Answer:

2069.76 N

Explanation:

density of wood = 824 kg/m^3

density of water = 1000 kg/m^3

Volume of wood = 1.2 m^3

True weight of wood = volume of wood x density of wood x gravity

True weight of wood = 1.2 x 824 x 9.8 = 9690.24 N

Buoyant force acting on wood = volume of wood x density of water x gravity

Buoyant force acting on wood = 1.2 x 1000 x 9.8 = 11760 N

Tension in the rope = Buoyant force - True weight

tension in rope = 11760 - 9690.24 = 2069.76 N

8 0

3 years ago

A watermelon is thrown down from a skyscraper with a speed of 7.0\,\dfrac{\text m}{\text s}7.0 s m 7, point, 0, space, start f

Degger [83]

Answer:

y = 17,89 m

Explanation:

Let us fixate the reference point in top of the building, from where the watermelon is thrown down. We will assume also that the positive axis of our system points up. We describe the watermelon’s motion with the equation:

$v_y^2 =v_0^2 + 2ay$

Clearing the equation so we isolate y we have that:

$y = (v_y^2 - v_0^2 )/2a$

Making a substitution with the values from the statement we have:

$y = ((20 m/s)^2 - (7 m/s)^2)/(2*9,81 m/s^2) = 17,89 m$ ]

So, this skyscraper is about 17,89 m tall; which is not very tall for a skyscraper but who am I to judge. 17,89 m is also the displacement of the watermelon from the point it was thrown down.

I hope everything was clear with my explanation. If I can help with anything else, just let me know. Have an awesome day :D

7 0

4 years ago

Read 2 more answers