1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Tanzania [10]
3 years ago
6

How many atoms are in 1.45 mol of pure aluminum

Chemistry
1 answer:
Serhud [2]3 years ago
7 0
Using Avogadro's number:

(1.45 mol)(6.022140857 x 10^23 atoms/mol) = 8.73 x 10^23 atoms

You might be interested in
How much money do you guys make off of this lame website?
MrRissso [65]

Answer:

so far from what i've seen its been 80 mil

Explanation:

the power of GoogIe

7 0
3 years ago
Read 2 more answers
PLEASE ANSWER ASAP
Sergio [31]

Answer:

Low level (altitude) clouds that are wispy and made of ice crystals.

precipitation and surface runoff

Hail

Nitrogen

Stratosphere

Decreases

Please Award Brainliest!

7 0
2 years ago
Read 2 more answers
13. A mixture of MgCO3 and MgCO3.3H2O has a mass of 3.883 g. After heating to drive off all the water the mass is 2.927 g. What
rjkz [21]

Answer:

63.05% of MgCO3.3H2O by mass

Explanation:

<em>of MgCO3.3H2O in the mixture?</em>

The difference in masses after heating the mixture = Mass of water. With the mass of water we can find its moles and the moles and mass of MgCO3.3H2O to find the mass percent as follows:

<em>Mass water:</em>

3.883g - 2.927g = 0.956g water

<em>Moles water -18.01g/mol-</em>

0.956g water * (1mol/18.01g) = 0.05308 moles H2O.

<em>Moles MgCO3.3H2O:</em>

0.05308 moles H2O * (1mol MgCO3.3H2O / 3mol H2O) =

0.01769 moles MgCO3.3H2O

<em>Mass MgCO3.3H2O -Molar mass: 138.3597g/mol-</em>

0.01769 moles MgCO3.3H2O * (138.3597g/mol) = 2.448g MgCO3.3H2O

<em>Mass percent:</em>

2.448g MgCO3.3H2O / 3.883g Mixture * 100 =

<h3>63.05% of MgCO3.3H2O by mass</h3>
6 0
3 years ago
The vapor pressure of 25 milliliters of water at 25 degrees celcius will be the same as
Marysya12 [62]
15 degrees Fahrenheit
8 0
3 years ago
How many moles of S would I have if I had 11 grams? (Stoichiometry) HELP
zepelin [54]
<h3>Answer:</h3>

0.34 mol S

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

11 g S

<u>Step 2: Identify Conversions</u>

[PT] Molar Mass of S - 32.07 g/mol

<u>Step 3: Convert</u>

  1. Set up:                                \displaystyle 11 \ g \ S(\frac{1 \ mol \ S}{32.07 \ g \ S})
  2. Multiply/Divide:                  \displaystyle 0.343 \ mol \ S

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

0.343 mol S ≈ 0.34 mol S

4 0
3 years ago
Other questions:
  • Given a 1.50 Liters of solution that contains 62.5 grams of magnesium oxide. What is the Molarity of that solution?
    13·1 answer
  • The minimum amount of methyl benzoate needed to trigger an alert for a drug dog is on the order of:
    10·1 answer
  • What reaction involves one element replacing an element in a compound that is from the same activity series?
    11·1 answer
  • Determine the net iconic equation for the following chemical reaction: HCl(aq) + NH4OH(aq)———-&gt; NH4Cl(aq) + H2O(I) Hint: HCl(
    12·1 answer
  • What is 694,563,239 rounded to the nearest thousand
    14·2 answers
  • 24g copper is submerged in water in a graduated cylinder, the total volume increases bu 2.7ml what is the density of copper
    10·1 answer
  • Pls help will give brainlist
    5·1 answer
  • How many Molecules are in 20 grams of CO?
    13·1 answer
  • Is this equation right? ​
    11·2 answers
  • ¿Quién estableció el concepto moderno de elemento?
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!