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Tanzania [10]
3 years ago
6

How many atoms are in 1.45 mol of pure aluminum

Chemistry
1 answer:
Serhud [2]3 years ago
7 0
Using Avogadro's number:

(1.45 mol)(6.022140857 x 10^23 atoms/mol) = 8.73 x 10^23 atoms

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Methane composes most of the natural gas.
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Only 20 plant species, such as rice, corn,and barely, make up the main sources of food for the entire human population.
riadik2000 [5.3K]

Answer:

I believe it would be D, to enhance the survival rate.

Explanation:

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A pool is 59.8 m long and 26.6 m wide. If the average depth of water is 3.70 ft, what is the mass (in kg) of water in the pool?
klio [65]

Given :

Length , l = 59.8 m.

Breadth , b  = 26.6 m.

Depth , d = 3.7 ft .

Density of water , \rho=1\ g/ml=1000\ kg/m^3 .

To Find :

Mass of water in pool .

Solution :

First we will covert depth into m from ft .

1\ ft =0.3\ m

For ,

3.7\ ft=0.3\times 3.7\ m\\3.7\ ft=1.11\ m

So , volume of pool is :

V=59.8\times 26.6\times 1.11\ m^3\\\\V=1765.65\ m^3

We know , density is given by :

\rho=\dfrac{m}{V}

So , m=\rho V

Putting given values in above equation :

m=1000\times 1765.65\ kg\\\\m=1.77\times 10^6\ kg

Hence , this is the required solution.

7 0
3 years ago
Why do solutions containing acids conduct an electric current?
Marizza181 [45]
The answers to this problem is C
7 0
2 years ago
Consider the following system at equilibrium:A(aq)+B(aq) <---> 2C(aq)Classify each of the following actions by whether it
velikii [3]

Explanation:

Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.

This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

  • On addition of reactant at equilibrium shifts the equilibrium in forward direction.
  • On addition of product at equilibrium shifts the equilibrium in backward direction.
  • On removal of reactant at equilibrium shifts the equilibrium in backward direction.
  • On removal of product at equilibrium shifts the equilibrium in forward direction.

A(aq)+B(aq)\rightleftharpoons 2C(aq)

Reactants = A , B

Product = C

1. Increase A

On increasing the amount of A at equilibrium will shift the equilibrium in forward or rightward direction.

2. Increase B

On increasing the amount of B at equilibrium will shift the equilibrium in forward or rightward direction.

3. Increase C

On increasing the amount of C at equilibrium will shift the equilibrium in backward or leftward direction.

4. Decease A

On decreasing the amount of A at equilibrium will shift the equilibrium in backward or leftward direction.

5. Decease B

On decreasing the amount of B at equilibrium will shift the equilibrium in backward or leftward direction.

6. Decease C

On decreasing the amount of C at equilibrium will shift the equilibrium in forward or rightward direction.

7. Double A and Halve B

Equilibrium constant of the reaction = K

K=\frac{[C]^2}{[A][B]}

On doubling A and halving B, equilibrium constant of the reaction = K'

K'=\frac{[C]^2}{[2A][\frac{B}{2}]}=\frac{[C]^2}{[A][B]}

The value of equilibrium constant K' is equal to K, which means that equilibrium will not shift in any direction.

8. Double both B and C

Equilibrium constant of the reaction = K

K=\frac{[C]^2}{[A][B]}

On doubling B and C, equilibrium constant of the reaction = K'

K'=\frac{[2C]^2}{[A][2B]}=\frac{4[C]^2}{[A][2B]}=\frac{2[C]^2}{[A][B]}

K' = 2 K

The value of equilibrium constant K' is double the K, which means that product is increasing which means that equilibrium will shift in backward or leftward direction.

5 0
3 years ago
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