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Tanzania [10]
3 years ago
6

How many atoms are in 1.45 mol of pure aluminum

Chemistry
1 answer:
Serhud [2]3 years ago
7 0
Using Avogadro's number:

(1.45 mol)(6.022140857 x 10^23 atoms/mol) = 8.73 x 10^23 atoms

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The element thallium is 70% thallium-205 and 30% thallium-203. Calculate its relative atomic mass to 1 decimal place.
xxMikexx [17]

Answer:

answer-

The relative atomic mass = 204.4

explanation:

Thallium -203 = 30%

Thallium -205 = 70%

Therefore ,

relative mass of thallium = (30×203 + 70×205)/100

relative mass of thallium = (20440)/100

relative mass of thallium = 204.40 amu

Thus,

relative atomic mass of thalium =204.4 ( to 1 decimal place)

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Goryan [66]

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prohojiy [21]

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<em>The correct option is A) Arrhenius</em>

Explanation:

According to the Arrhenius concept of acids and bases, an acid must produce H+ ions when it is present in a solution and the base must produce OH- ions when placed in a solution.

Ammonia does not contain OH- ions of its own when dissolved in water.

The reaction of ammonia dissolving is water can be written as:

NH3     +    H2O     ⇌   NH4+ + OH−

As we can see from the equation, ammonia does form OH- ions but it does not have OH- ions on its own.

Hence, according to the Arrhenius concept, NH3 is not a base.

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If u are multiplaying it would be 80 percent more likely
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The chemical formula for water, h2o, means that each water molecule contains
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