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Tanzania [10]
3 years ago
6

How many atoms are in 1.45 mol of pure aluminum

Chemistry
1 answer:
Serhud [2]3 years ago
7 0
Using Avogadro's number:

(1.45 mol)(6.022140857 x 10^23 atoms/mol) = 8.73 x 10^23 atoms

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Which is more dense a pound of rice or a pond of cement
Ann [662]
A pond of cement is more dense
4 0
3 years ago
Calculate the entropy change when a. two moles of H2O(g) are cooled irreversibly at constant p from 120°C to 100°C. b. one mole
alexira [117]

Answer:

The problem solution is given in the attachments.

3 0
3 years ago
Plz someone help, really struggling
frez [133]

Answer:

22.9 Liters CO(g) needed

Explanation:

2CO(g)     +   O₂(g)    =>    2CO₂(g)

? Liters          32.65g

                 = 32.65g/32g/mol

                 =   1.02 moles O₂

Rxn ratio for CO to O₂ = 2 mole CO(g) to 1 mole O₂(g)

∴moles CO(g) needed = 2 x 1.02 moles CO(g) = 2.04 moles CO(g)

Conditions of standard equation* is STP (0°C & 1atm) => 1 mole any gas occupies 22.4 Liters.

∴Volume of CO(g) = 1.02mole x 22.4Liters/mole = 22.9 Liters CO(g) needed

___________________

*Standard Equation => molecular rxn balanced to smallest whole number ratio coefficients is assumed to be at STP conditions (0°C & 1atm).

6 0
2 years ago
A chemical reaction that removes electrons from an atom is called a(n) ________ reaction.
ch4aika [34]
A chemical reaction that removes electrons from an atom is called "O<span>xidation".
The term came from late 18th century from French.
When the electrons are removed from an atom it increase its valence.</span>
3 0
3 years ago
Under standard-state conditions, which of the following half-reactions occurs at the cathode during the electrolysis of aqueous
Slav-nsk [51]

Answer:

The following reaction will occur at cathode:

Ni^{+2}(aq)+2e--->Ni(s)

Explanation:

The two half reaction during electrolysis of aqueous nickel sulfate will be

a) anode reaction :

Water will undergo oxidation and will evolve oxygen gas at anode as shown in the given reaction:

2H_{2}O(l) ----> O_{2}(g) + 4H^{+}(aq) + 4e

b) Cathode reaction: The reduction of Nickel ion will occur by gain of two electrons as shown in the given equation:

Ni^{+2}(aq)+2e--->Ni(s)

Thus the overall reaction will be:

2H_{2}O(l) + 2Ni^{+2}----> O_{2}(g) + 4H^{+}(aq) + 2Ni(s)

6 0
3 years ago
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