Answer:
I think the right answer is c/ number of atomic orbitals
Answer:
39.1 °C
Explanation:
Recall the equation for specific heat:

Where q is the heat, m is the mass, c is the specific heat of the substance (in this case water), and delta T is the change in temperature.
You should know that the specific heat of water is 1 cal/g/C.
Using the information in the question:

The final temperature is about 39.1 °C.
If the temperature of the sample of gas increases to the given value, the volume also increases to 600mL.
<h3>What is Charles's law?</h3>
Charles's law states that "the volume occupied by a definite quantity of gas is directly proportional to its absolute temperature.
It is expressed as;
V₁/T₁ = V₂/T₂
Given the data in the question;
- Initial temperature of gas T₁ = 100K
- Initial volume of gas V₁ = 300mL
- Final temperature T₂ = 200K
V₁/T₁ = V₂/T₂
V₂ = V₁T₂ / T₁
V₂ = ( 300mL × 200K ) / 100K
V₂ = 60000mLK / 100K
V₂ = 600mL
Therefore, if the temperature of the sample of gas increases to the given value, the volume also increases to 600mL.
Learn more about Charles's law here: brainly.com/question/12835309
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Answer:
pH ≅ 4.80
Explanation:
Given that:
the volume of HN₃ = 25 mL = 0.025 L
Molarity of HN₃ = 0.150 M
number of moles of HN₃ = 0.025 × 0.150
number of moles of HN₃ = 0.00375 mol
Molarity of NaOH = 0.150 M
the volume of NaOH = 13.3 mL = 0.0133
number of moles of NaOH = 0.0133× 0.150
number of moles of NaOH = 0.001995 mol
The chemical equation for the reaction of this process can be written as:

1 mole of hydrazoic acid react with 1 mole of hydroxide to give nitride ion and water
thus the new number of moles of HN₃ = 0.00375 - 0.001995 = 0.001755 mol
Total volume used in the reaction = 0.025 + 0.0133 = 0.0383 L
Concentration of
=
= 0.0458 M
Concentration of
=
= 0.0521 M
GIven that :
Ka = 
Thus; it's pKa = 4.72




pH ≅ 4.80