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2 years ago

What is the molarity of 2 moles of a compound dissolved in 4 L of water?

Chemistry

1 answer:

Akimi4 [234]2 years ago

4 0

Answer:

$\boxed {\boxed {\sf B. \ 0.5 \ M}}$

Explanation:

Molarity is a measure of concentration in moles per liter. The formula for calculating molarity is:

$molarity= \frac{moles \ of \ solute}{ liters \ of \ solution}$

There are 2 moles of a compound or the solute. There are 4 liters of water or the solution.

moles of solute= 2 mol
liters of solution = 4 L

Substitute the values into the formula.

$molarity = \frac{ 2 \ mol}{ 4 \ L}$

Divide.

$molarity= 0.5 \ mol /L$

1 mole per liter is equal to 1 Molar, so the solution's molarity of 0.5 mol/L is equal to 0.5 M.

$molarity = 0.5 \ M$

The molarity of the solution is 0.5 Molar and choice B is correct.

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The structural formula of 2-methyl-propane<br>-2-ol

daser333 [38]

Answer:

ch3c(ch3)(oh)ch3

Explanation:

that should be the answer

8 0

2 years ago

how many moles of potassium dichromate (k2cr2o7) are required to prepare a 250-ml solution of with a concentration of 2.16 m?

Eva8 [605]

The moles of potassium dichromate , K₂Cr₂O₇ are required to prepare a 250 mL solution of with a concentration of 2.16 M is 0.54 mol.

given that :

molarity = 2.16 M

volume = 250 mL = 0.25 L

the molarity is given as :

molarity = number of moles / volumes in L

from this we can calculate the number of moles, we get :

number of moles of K₂Cr₂O₇ = molarity × volume

number of moles of K₂Cr₂O₇ = 2.16 × 0.25

number of moles of K₂Cr₂O₇ = 0.54 mol

Thus, The moles of potassium dichromate , K₂Cr₂O₇ are required to prepare a 250 mL solution of with a concentration of 2.16 M is 0.54 mol.

To learn more about moles here

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4 0

1 year ago

Arrange these elements based on their atomic radii. ga, f, s, as

mamaluj [8]

please have look at Periodic table , you will solve it yourself !

5 0

3 years ago

What is the molarity of a NaOH solution if 28.2 mL of a 0.355 M H2SO4 solution is required to neutralize a 25.0-mL sample of the

Verdich [7]

Answer:

[NaOH} = 0.4 M

Explanation:

In a reaction of neutralization, we determine the equivalence point of the titration. In this case, we have a strong base and a strong acid.

(H₂SO₄, is considered strong, but the first deprotonation is weak)

2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O

As we have 2 protons in the acid, we need 2 OH⁻ from the base to form 2 molecules of water.

In the equivalence point we know mmoles of base = mmoles of acid

Let's finish the excersise with the formula

25 mL . M NaOH = 28.2 mL . 0.355M

M NaOH = (28.2 mL . 0.355M) / 25 mL → 0.400

8 0

3 years ago

Two hydrogen atoms collide in a head on collision and end up with zero kinetic energy. Each then emits a photon of 121.6 nm (n=2

Zinaida [17]

Explanation:

Expression for the kinetic energy is as follows.

K.E = $\frac{1}{2}mv^{2}$

Now, total kinetic energy will be as follows.

K.E = $2 \times \frac{1}{2}mv^{2}$ = $m \times v^{2}$

Since, this energy converts into electromagnetic radiation of wavelength 121.6 nm.

Relation between energy and photon is as follows.

Energy of photon = $\frac{hc}{\lambda}$

= $\frac{6.626 \times 10^{-34} \times 3 \times 10^{8}}{121.6 \times 10^{-9}}$

= $1.63 \times 10^{-18} J$

$m \times v^{2} = 1.63 \times 10^{-18}$

v = $\sqrt{\frac{1.63 \times 10^{-18}}{1.67 \times 10^{-27}}$

= $3.12 \times 10^{4}$ m/s

Thus, we can conclude that atoms were moving at a speed of $3.12 \times 10^{4}$ m/s before the collision.

8 0

3 years ago