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garri49 [273]
2 years ago
11

Can someone answer this

Mathematics
1 answer:
sladkih [1.3K]2 years ago
8 0

Answer:

mnbvcxzasdfghjkoiuytrew

Step-by-step explanation:

mnbvcxzasdfghj play amoung us

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pogonyaev
50/100
5/10
hope that helped :)
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3 years ago
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Which values of x make this equation true?
Evgesh-ka [11]

Answer:

{x}^{2}  + x = 12 \\  {x}^{2}  + x - 12 = 0 \\  {x }^{2}  + 4x - 3x - 12 = 0 \\ x(x + 4) - 3(x + 4) = 0 \\ (x + 4)(x - 3) = 0 \\ either \:  \:  \: or \:  \\ x =  - 4 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: x = 3

the answer is -4 and 3

3 0
2 years ago
1) After a dilation, (-60, 15) is the image of (-12, 3). What are the coordinates of the image of (-2,-7) after the same dilatio
BARSIC [14]

Answer:

a) k = 5; (-10, -35)

Step-by-step explanation:

Given:

Co-ordinates:

Pre-Image = (-12,3)

After dilation

Image = (-60,15)

The dilation about the origin can be given as :

Pre-Image(x,y)\rightarrow Image(kx,ky)

where k represents the scalar factor.

We can find value of k for the given co-ordinates by finding the ratio of x or y co-ordinates of the image and pre-image.

k=\frac{Image}{Pre-Image}

For the given co-ordinates.

Pre-Image = (-12,3)

Image = (-60,15)

The value of k=\frac{-60}{-12}=5

or k=\frac{15}{3}=5

As we get k=5 for both ratios i.e of x and  y co-ordinates, so we can say the image has been dilated by a factor of 5 about the origin.

To find the image of (-2,-7), after same dilation, we will multiply the co-ordinates with the scalar factor.

Pre-Image(-2,-7)\rightarrow Image((-2\times5),(-7\times 5))

Pre-Image(-2,-7)\rightarrow Image(-10,-35) (Answer)

7 0
2 years ago
The probability of an event happening is 5/9 what are the odds in favor of the event happening
rosijanka [135]

Answer:

5/9

Step-by-step explanation:

it's literally telling you the answer and asking you

If they want the odds in favor then it's the odds of the event happening

7 0
2 years ago
Suppose two fractions are both less than 1. Can their sum be greater than 1? Greater than 2?
Juliette [100K]
Their sum can be greater than two. There is nothing that states that they couldn't be. All it states it that the two factions sums are less than 1. I hoped this helps 
4 0
3 years ago
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