3 years ago

An car is brought to rest in a distance of 652 m using a constant acceleration of -2.7 m/s2. What was the

Physics

1 answer:

Goshia [24]3 years ago

7 0

Answer:

I’m so sorry I tried solving it but I don’t understand it can you explain the question a little bit more ty

Explanation:

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Via half-life equation we have:

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A piece of taffy slams into and sticks to another identical piece of taffy that is at rest. The momentum of the two pieces stuck

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Answer:0.5

Explanation:

Given

Piece of taffy slams in to sticks to another identical piece and stuck into it.

Let m be the mass of taffy and u be the initial velocity of taffy and v be the final velocity of system.

Conserving momentum

$mu=2mv$

$v=\frac{u}{2}$

Initial kinetic energy $=\frac{mu^2}{2}$

Final Kinetic Energy $=\frac{2m(\frac{u}{2})^2}{2}=\frac{mu^2}{4}$

change in kinetic energy $\Delta K.E.=\frac{mu^2}{2}-\frac{mu^2}{4}=\frac{mu^2}{4}$

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