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Korvikt [17]
3 years ago
9

What are three characteristics a koala probably inherited from its parent

Physics
1 answer:
FromTheMoon [43]3 years ago
5 0
Its ears taste and nose ur welcome
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Which phrases describe all the outer planets’ motion? Select two options.
AysviL [449]

Answer:

Fast rotation

Slow revolution

Explanation:

Solar system has 8 planets. 4 inner rocky planets - Mercury, Venus, Earth and Mars and 4 outer gaseous planets - Jupiter, Saturn, Uranus and Neptune.  The outer planets have few common features.

They are gaseous. There  period of revolution is larger than the inner planets which means that they have slow revolution about the Sun. One day on the outer planets is smaller than the inner planets which means they have fast rotation.

For example, Jupiter has revolves around sun in 11.86 Earth years and rotates about axis in 9.8 Earth hours. Uranus revolves around sun in 84 Earth years and rotates on its axis 17.9 Earth hours.

8 0
3 years ago
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If two waves interact in destructive interference, which of the following will be true regarding the new wave formed?
AlekseyPX

Answer:

b

Explanation:

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Answer:

yes

Explanation:

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"A capacitor charged to 1.5 V stores 2.0 mJ of energy. Determine the energy stored in the capacitor if it is charged to 3.0 V."
Salsk061 [2.6K]

To solve this problem we will apply the concepts related to electric potential energy. This relationship shows us that energy is equivalent to half the product between the capacitance of the body by the squared voltage. Mathematically it can be expressed as,

E = \frac{1}{2} CV^2

Here,

C = Capacitance

V = Voltage

E = Energy

The initial capacitance would then be given by

2mJ = \frac{1}{2} C (1.5)^2

C = \frac{4*10^{-3}}{(1.5)^2}

C = 1.78*10^{-3}F

Energy stored in the capacitor with 3V is

E = \frac{1}{2} (1.78*10^{-3})(3)^2

E = 8mJ

Therefore the energy stored in the capacitor if it is charged to 3V is 8mJ

8 0
3 years ago
A small Styrofoam bead with a charge of −60.0 nC is at the center of an insulating plastic spherical shell with an inner radius
Romashka-Z-Leto [24]

Answer:

speed of the proton is 6.286 ×10^{5} m/s

Explanation:

given data

charge  q= −60.0 nC

inner radius a = 20.0 cm

outer radius b = 24.0 cm

charge density ρ = −2.05 µC/m³

to find out

What is the speed of the proton

solution

we know that force on the proton due to this electric field is express as

F = q × E      ...................1

here F is force and q is charge and E is electric filed so

if v be the speed of the proton in circular orbit than  force will be

F = \frac{mv^2}{b}       ....................2

from equation 1 and 2

q × E = \frac{mv^2}{b}     .......................3

so

here total charge Q on shell is

Q = ρ × V

here ρ is density and V is volume

Q = \rho * \frac{4}{3} \pi  (b^3-a^3)

put here value

Q = -2.05*10^{-6} \frac{4}{3} \pi  (0.24^3-0.20^3)

Q = 50.01 × 10^{-9} C

and

total charge enclosed by Gaussian surface is

qin = q + Q

qin = −60  × 10^{-9} C - 50.01 × 10^{-9} C

qin = - 110.01 × 10^{-9} C

and

from Gauss law

\oint E*A = \frac{\left | qin \right | }{\epsilon }

E ×4×π×b² =  \frac{110.01*10^{-9} }{\epsilon }

E = \frac{110.01*10^{-9} }{\epsilon *4 *\pi *b^2[tex]}

E = \frac{9*10^9 * 110.01*10^{-9} }{0.24^2}

E = 17189.06 N/C

so

from equation 3

q × E = \frac{mv^2}{b}  

v = \sqrt{\frac{q*E*b}{m}}

v = \sqrt{\frac{1.6*10^{-19}*17189.06*0.24}{1.67*10^{-27}}}

v = 6.286 ×10^{5} m/s

so speed of the proton is 6.286 ×10^{5} m/s

4 0
3 years ago
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