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andrew-mc [135]
3 years ago
7

How do the meetings of the words exercise and fitness differ?

Physics
1 answer:
ICE Princess25 [194]3 years ago
7 0
Exercise is the activity and fitness is a lifestyle and done with time
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A person can see clearly up close but cannot focus on objects beyond 75.0 cm. She opts for contact lenses to correct her vision.
Pavel [41]

Answer:

(a) nearsighted

(b) diverging

(c) the lens strength in diopters is 1.33 D, and considering the convention for divergent lenses normally prescribed as: -1 33 D

Explanation:

(a) The person is nearsighted because he/she cannot see objects at distances larger than 75 cm.

(b) the type of correcting lens has to be such that it counteracts the excessive converging power of the eye of the person, so the lens has to be diverging (which by the way carries by convention a negative focal length)

(c) the absolute value of the focal length (f) is given by the formula:

f=\frac{1}{d} =\frac{1}{0.75} = 1.33\,D

So it would normally be written with a negative signs in front indicating a divergent lens.

7 0
3 years ago
Jupiter is 317 times more massive than the Earth. Its gravitational attraction is _____ Earth's.
NeTakaya
That all depends on your distance from the center of each planet.

On the surface of Jupiter, the acceleration of gravity is 2.53 times
its value on the surface of the Earth.
6 0
3 years ago
Read 2 more answers
A wave traveling in the positive x-direction with a frequency of 50.0 Hz is shown in the figure below. Find the following values
Klio2033 [76]

Answer:

Explanation:

a. The amplitude is the measure of the height of the wave from the midline to the top of the wave or the midline to the bottom of the wave (called crests). The midline then divides the whole height in half. Thus, the amplitude of this wave is 9.0 cm.

b. Wavelength is measured from the highest point of one wave to the highest point of the next wave (or from the lowest point of one wave to the lowest point of the next wave, since they are the same). The wavelength of this wave then is 20.0 cm. or \lambda=20.0cm

c. The period, or T, of a wave is found in the equation

f=\frac{1}{T} were f is the frequency of the wave. We were given the frequency, so we plug that in and solve for T:

50.0=\frac{1}{T} so

T=\frac{1}{50.0} and

T = .0200 seconds to the correct number of sig fig's (50.0 has 3 sig fig's in it)

d. The speed of the wave is found in the equation

f=\frac{v}{\lambda} and since we already have the frequency and we solved for the wavelength already, filling in:

50.0=\frac{v}{20.0} and

v = 50.0(20.0) so

v = 1.00 × 10³ m/s

And there you go!

5 0
3 years ago
The displacement of a moving object in given interval of time is zero . Would the distance travelled by the object also be zero.
kirill [66]





Hi Pupil Here's Your answer ::




➡➡➡➡➡➡➡➡➡➡➡➡➡



No, on a circle in going from one point around circular path the displacement is zero but the distance covered is equal to the circumference of the circle.

i.e.


2\pi r


⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅




Hope this helps . . . . . . .

3 0
3 years ago
A force of 450 N accelerates a box across a frictionless surface at a rate of 15 m/s 2 . What is the mass of the box?
kow [346]
Used Mephyso for the calculation

8 0
4 years ago
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