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Kamila [148]
4 years ago
7

PLEASE HELP!! numbers 10 and 12 please :)

Mathematics
1 answer:
Marianna [84]4 years ago
5 0
10) x=<span>2<span>y</span></span>
12) x=<span><span><span>14</span>y</span>−1
 hope this helps! :)

</span>
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Which equation represents a line which is perpendicular to the line 4x + 3y = - 24 ?
Scorpion4ik [409]

Answer:

C

Step-by-step explanation:

4x+3y=-24

eq. of any line perpendicular to given line is

3x-4y=a

4y=3x-a

y=3/4x -a/4

where a is an arbitrary constant.

4 0
3 years ago
Write an equation of the line that passes through (-2, 8) and (-4, -4)
Nady [450]

Answer:

y=6x+20

Step-by-step explanation:


6 0
4 years ago
The grades in a statistics course for a particular semester were as follows:
ziro4ka [17]

Answer:

Test Statistic = 10

Critical Value = 9.488

Step-by-step explanation:

Given :

Grade A _ B _ C _ D _ F

_____14 _ 18 _32_ 20_16

H0 : distribution of grade is uniform

H1 : Distribution of grade is not uniform

Using the Chisquare statistic :

χ² = (observed - Expected)² / Expected

The expected value :

(14+18+32+20+16) / 5 = 20

χ² = (14-20)^2 / 20 + (18-20)^2 / 20 + (32-20)^2 / 20 + (20-20)^2 / 20 + (16-20)^2 / 20

χ² statistic = 10

The χ² critical at df = (n - 1) = 5 - 1 = 4

χ² Critical(10, 4) = 9.488

8 0
3 years ago
5. If we represent the length of a line by a,
Liono4ka [1.6K]

Answer:

Step-by-step explanation:Let a be the length of line

from question we know that

a+3 is another line

Here

a+(a+3)=15. ( Given in question )

2a = 15 -3

2a=12

a=12/2

a=6

Here a and a +3 are the length of the line

Finally ,6 and 9 are the lengths

7 0
3 years ago
Find the sum of the first five terms using the geometric series formula for the sequence left curly bracket 1 half comma space m
MatroZZZ [7]

Answer:

\bold{\dfrac{11}{2 }}

Step-by-step explanation:

Given the geometric series:

\{\dfrac{1}2, -1, 2, -4,  ..... \}

To find:

Sum of series upto 5 terms using the geometric series formula = ?

Solution:

Formula for sum of a n terms of a geometric series is given as:

S_n=\dfrac{a(1-r^n)}{1-r} \ \{r

a is the first term of the geometric series

r is the common ratio between each term (2nd term divided by 1st term or 3rd term divided by 2nd term ..... ).

Here:

a = \dfrac{1}{2}

r = \dfrac{-1}{\dfrac{1}{2}} = -2

n=5

So, applying the formula for given values:

S_5=\dfrac{\dfrac{1}2(1-(-2)^5)}{1-(-2)} \\\Rightarrow S_5=\dfrac{1-(-32)}{2 \times 3} \\\Rightarrow S_5=\dfrac{1+32}{6} \\\Rightarrow S_5=\dfrac{33}{6} \\\Rightarrow \bold{S_5=\dfrac{11}{2}}

So, the answer is

\bold{\dfrac{11}{2 }}

3 0
4 years ago
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