5x^2+3x^2 Simplify the polynomial

Mathematics

1 answer:

iris [78.8K]4 years ago

7 0

Answer: it would be 8x↑2

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Chandra bought a 2-liter bottle of

tatuchka [14]

Answer:B

Step-by-step explanation:

Divide by 8 and look at the whole number

3 0

4 years ago

Iris tenía cierta cantidad de dinero por su cumpleaños su mamá le dio 20 soles después tu papá le dio el triple de lo que ya ten

Alisiya [41]

Resultado:

${ \: \: \: \: \: \: \: \: \: \Rightarrow 20 + 60 + 80 = 160}$

$\: \: \: \: \: \: \: \: \: \sf \Rightarrow20+60+80=160$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: { \sf \Rightarrow160 - 100 = 60}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf \Rightarrow160−100=60$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: { \sf \Rightarrow100 - 60 = 40}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: { \sf \Rightarrow100−60=40}$

$\: \: \: \: \: \: \sf \Rightarrow60 + 40 + 100 = 200$

$\: \: \: \: \: \: \: { \sf \Rightarrow60+40+100=200}$

$\bf\green{\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\: Answer :}$

Iris al principio tenía 40 soles.

Espero que te sirva, salu2!!!!

3 0

2 years ago

Read 2 more answers

For the function F(x) = 2x^2-31x-51, where is the function increasing and positive? ( for all X values greater than what number

Ulleksa [173]

ANSWER
$x \: > \: 17$

EXPLANATION

The given function is

$f(x) = 2 {x}^{2} - 31x - 51$
Let us split the middle term to get,

$f(x) = 2 {x}^{2} -34x + 3x- 51$

We factor to obtain,

$f(x) = 2x(x - 17) -+3(x - 17)$

$f(x) = (2x -+3)(x -17)$

Let us find the zeros of f(x),

$(2x +3)(x - 17) = 0$

Either

$2x +3 = 0 \: or \: x - 17 = 0$
$x = -\frac{3}{2} \: or \: x = 17$

We need to find the x-value of the vertex, which is the midpoint of the x-intercepts.

This gives us,

$\frac{- \frac{3}{2} + 17}{2} = 7.75$
Hence the axis of symmetry of the parabola has equation,

$x = 7.75$

Since the given function has minimum turning point, it will decrease and then increase.

The function will be increasing for
$x \: > \: 7.75$

The function will be increasing and positive for
$x \: > \: 17$