Something funny is that the x value of the vertex lies directl in the middle of the x intercepts
so
we see the x intercepts or 0's at x=8 and 2
the average is x=5
so find f(5) to find the y value of the vertex
f(5)=(5-8)(5-2)
f(5)=(-3)(3)
f(5)=-9
vertex is at (5,-9)
the actual way the teacher wants is to expand then compltete the square to get into the form f(x)=a(x-h)^2+k where the vertex is (h,k)
but whatever
verrtex is at (5,-9)
Answer:
yoo
Step-by-step explanation:
Answer:
6x - 11y = -13 is the answer.
Step-by-step explanation:
Let's plug in the points to see what sticks.
Start with (-4, -1)
1) 11x - 6y = 11(-4) - 6(-1) = -44 + 6 = -38
13
2) 6x - 11y = 6(-4) - 11(-1) = -24 + 11 = -13
3) 6x - 7y = 6(-4) - 7(-1) = -24 + 7 = -17
17
4) 6x - 11y = 6(-4) - 11(-1) = -24 + 11 = -13
13
The only one that fits is #2. Let's try the other point to be sure.
2) 6x - 11y = 6(1.5) - 11(2) = 9 - 22 = -13
Answer:
Not proportional
Step-by-step explanation:
If you just Find the unit rate of each thing, you’ll find that none of them are equal to each other.
I think it is 1/3 but I am not sure. Sorry if wrong.